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sertanlavr [38]
3 years ago
9

Please help ill give brainliest thanks and all 5 stars:((((((

Mathematics
2 answers:
igomit [66]3 years ago
7 0

Answer:

20

Step-by-step explanation:

Okay, so you can see x= 26, so you half it. You do this because it says 1/2. Then it says plus 7, 7 plus 13 equals 20. Therefore y= 20

pashok25 [27]3 years ago
5 0
The answer would be 20
Because if x is 26 then your equation would now be y=1/2(26)+7
So no you would multiply 1/2 times 26 which gives you 13 okay so now your equation should be y=13+7 and now you just add 13+7 which gives you 20 and there you go
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meriva
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if diameter = 1.680 then radius = 1/2 * 1.680 = 0.84

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What value of x makes the equation true? <br> A.1<br> B.-5<br> C.-1<br> D.7
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find the dimensions of the sports field at the right if the width is at least 60 yards AREA = 240 - 400X SQUARE YARDS
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Answer:

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Width of the sports field = At least 60 yards

Area of the sports field = 240 - 400x square yards

We can conclude the shape of the sports field is rectangular.

2. Find the dimensions of the sports field.

A. We need to find the Greatest Common factor between 240 and 400, this way:

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240 .

The factors of 400 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, 400 .

Then the greatest common factor is 80.

This GCF is also higher than 60, therefore it's one of the dimensions of the sports field.

Now, we calculate the other side of the sports, this way:

Second dimension of the sports field = (240 - 400x)/80

Second dimension of the sports field = 3 -5x

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

8 0
3 years ago
Need help with this stuck on another problem
Cerrena [4.2K]

just remove perenthesis

5 0
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Does anyone know the answers to these?
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Step-by-step explanation:

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At 31 degrees of freedom and 98% confidence, t = 2.453.

The margin of error is therefore:

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MoE = 4.42

c.  The confidence interval is:

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CI = (42.58, 51.42)

d. We can conclude with 98% confidence that the true mean is between 42.58 days and 51.42 days.

e. We can reduce the margin of error by either increasing the sample size, or using a lower confidence level.

3 0
3 years ago
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