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Which term best describes a figure formed by three segments connecting

elixir [45]

Answer:

The term that best describes a figure formed by three segments connecting three non-collinear points is:

Triangle.

Step-by-step explanation:

Step-by-step explanation:

We know that with the help of just one point we can't form any figure.

With the help of two points a line segment can be formed.

And with the help of three points if the three points are collinear a triangle can be formed.

Hence, the term that best describes a figure formed by three segments connecting three non-collinear points is:

Triangle.

8 0

3 years ago

Is x-2 a factor of f(x)=6x^2-7x-5

Paha777 [63]

Answer:

its not

Step-by-step explanation:

if you do the division euclidiene the rest will be 5 not zero

f(x)=(x-2)(6x+5)+5

7 0

2 years ago

A tank initially has 300 gallons of a solution that contains 50 lb. of dissolved salt. A brine solution with a concentration of

belka [17]

Let s(t) be the amount of salt in the tank at time t. Then s(0) = 50 lb.

Salt flows into the tank at a rate of

(2 gal/min) (6 lb/gal) = 12 lb/min

and flows out at a rate of

(2 gal/min) (s(t)/300 lb/gal) = s(t)/150 lb/min

so that the net rate at which salt is exchanged through the tank is

ds(t)/dt = 12 - s(t)/150 … (lb/min)

Solve for s(t). The DE is separable, so we have

ds/dt = 12 - s/150

150 ds/dt = 1800 - s

150/(1800 - s) ds = dt

Integrate both sides to get

-150 ln|1800 - s| = t + C

Solve for s :

ln|1800 - s| = -t/150 + C

1800 - s = exp(-t/150 + C )

1800 - s = C exp(-t/150)

s = 1800 - C exp(-t/150)

Now given that s(0) = 50, we solve for C :

50 = 1800 - C exp(-0/150)

50 = 1800 - C

C = 1750

Then the amount of salt in the tank at any time t ≥ 0 is

s(t) = 1800 - 1750 exp(-t/150)

To find the time it takes for the tank to hold 100 lb of salt, solve for t in

100 = 1800 - 1750 exp(-t/150)

1700 = 1750 exp(-t/150)

34/35 = exp(-t/150)

ln(34/35) = -t/150

t = -150 ln(34/35) ≈ 4.348

So it would take approximately 4.348 minutes.

By the way, we didn't have to solve for s(t), we could have instead stopped with

-150 ln|1800 - s| = t + C

Solve for C - this C is not the same as the one we found using the other method. s(0) = 50, so

-150 ln|1800 - 50| = 0 + C

C = -150 ln|1750|

==> t = 150 ln(1750) - 150 ln|1800 - s|

Then s(t) = 100 lb when

t = 150 ln(1750) - 150 ln(1700)

t = 150 ln(1750/1700)

t = 150 ln(35/34)

t ≈ 4.348

5 0

3 years ago

Is (10,2) a solution to the equation 3y+14=2x?

Sergio [31]

Answer:

yes

Step-by-step explanation:

Use substitution method

3(2)+14=2(10)

6+14=20

20=20

Hope this helps. Have a nice day you amazing bean child.

4 0

3 years ago

Which equation represents a line that passes through two points in the table

Anvisha [2.4K]

C. y - 3 = 2/3(x-3)

Nothing much to do here except examine each equation and plug in the numbers to see if it's true.

a. y + 3 = 3/2(x+3)
Try 3,3
3 + 3 = 3/2(3+3)
6 = 3/2(6). And no need to go further, it's obviously not equal.

b. y - 3 = 3/2(x-3)
Try 3,3
3 - 3 = 3/2(3-3)
0 = 3/2(0). OK. Let's try 6,5
5 - 3 = 3/2(6-3)
2 = 3/2(3)
2 = 9/2 And it's not true, so check the next one.

c. y - 3 = 2/3(x-3)
Try 3,3
3 - 3 = 2/3(3-3)
0 = 0. Check 6,5
5 - 3 = 2/3(6-3)
2 = 2/3(3)
2 = 2. Good. Both sample points work. This is the correct answer.
Just to be sure, let's check the next option

d. y + 3 = 2/3(x+3)
Try 3,3
3 + 3 = 2/3(3+3)
6 = 2/3(6). And doesn't match.

6 0

3 years ago