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pshichka [43]
3 years ago
11

How would using a number line to find the sum -2+ -5?

Mathematics
1 answer:
Gelneren [198K]3 years ago
3 0

Answer:

In finding the sum of 2+5 you would go right on the number line, while in finding the sum of -2+(-5) you would go left on the number line

Step-by-step explanation:

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yanalaym [24]

Answer:

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Step-by-step explanation:

To solve all of these questions you just need to scale. While scaling you can divide or multiply.

1. \frac{180 km}{4 hrs} (divide by 4 to get unit rate)

     unit rate = \frac{45km}{1hr}

2. If it takes one hour to travel 40 miles, then we don't have to scale or anything. We know \frac{40 miles}{1 hr}, the answer is...

"It'll only take one hour to travel 40 miles. This is correct because the unit rate is \frac{40 miles}{1 hr}. "

3. Knowing that the constant speed of the plane is \frac{800 km}{1 hour\\}, we can scale then add half of the unit rate to get our answer.

\frac{800 km}{1 hour\\} x 3 = \frac{2400 km}{3 hrs}   800 x 3 = 2400

then add half of unit rate which is \frac{400 km}{30 mins}  \sqrt[2]{800} = 400

so, our answer is \frac{2800 km}{3.5 hours}

4.  \frac{3km}{30 mins} <--- ( divided by 2) \frac{6 km}{1 hr} ( multiplied x 2.5) ---> \frac{15 km}{2.5 hrs}

To get an easier way to find the answer, if possible you can scale back farther than the 1 hour mark.

Elmer would take 2 and a half hours to ride 15 km.

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3 0
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Answer:

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6 0
3 years ago
Read 2 more answers
If point C is between A and B, then AC + CB=_____<br><br> A. ABC<br> B. BC<br> C. AB<br> D. CA
velikii [3]

The answer is C. AB. The total line segment is ACB, or AB, because C is in between A and B. If you are adding AC and CB together, you are adding the two parts of the line together.

I hope this helps :)

7 0
3 years ago
Find the product.
4vir4ik [10]
Answer :

6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}

Step-by-step explanation :

To find the product of

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)

we now apply the law of indices

{a}^{m} \times {a}^{n} = {a}^{m+n}

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}
3 0
3 years ago
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