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3 years ago

5

3 (x - 3) + x (r + 4)

1 answer:

docker41 [41]3 years ago

7 0

Answer:

Step-by-step explanation:

3(x-3)+x(r+4)

3x-9+xr+4x

7x+9+xr

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You guys are life savers but does anyone know the answers to these questions? I’m so confused rn

timofeeve [1]

Answer:

The third choice

Step-by-step explanation:

We need to find the slope and y-intercept of the line and then put it into y = mx = b form. To find the slope, pick a point on the line; I will use (-2, 5); count how many units up you need to go to get to the next point on the line, which in this case it would be 3. The count how many to the right or left you would need to go, which is 1 to the left. Moving left means a negative, so it is -1. Your slope fraction would be $\frac{3}{-1}$ , since slope is rise over run. You can sub this fraction in for m in y = mx + b, which will give you a revised equation of y = -3x = b. To find the y intercept, or b, just find the point where the line crosses the y-axis, which is -1. So, the equation is now y = -3x - 1.The correct answer is third choice.

6 0

3 years ago

PLZZZZZZZZZZZZZZZZZZZZZZZ help I will give brainliest for right answer!

lubasha [3.4K]

Got me there but i think its 325500

3 0

2 years ago

Read 2 more answers

Noah has a summer tree-trimming business. Based on experience, Noah knows that his profit, P, in dollars, can be modelled by = −

crimeas [40]

Solving quadratic equations, it is found that he needs to charge:

1. He needs to charge $40 to break even.

2. He needs to charge $30 for a profit of $600.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

$y = ax^2 + bx + c$

The solutions are:

$x_1 = \frac{-b + \sqrt{\Delta}}{2a}$

$x_2 = \frac{-b - \sqrt{\Delta}}{2a}$

In which:

$\Delta = b^2 - 4ac$

The profit equation in this problem is:

P(x) = -3x² + 150x - 1200.

He breaks even when P(x) = 0, hence:

-3x² + 150x - 1200 = 0.

The coefficients are a = -3, b = 150, c = -1200, hence:

$\Delta = 150^2 - 4(-3)(-1200) = 8100$

$x_1 = \frac{-150 + \sqrt{8100}}{-6}$

$x_2 = \frac{-150 - \sqrt{8100}}{-6} = 40$

He needs to charge $40 to break even.

For a profit of $600, we have that P(x) = 600, hence:

-3x² + 150x - 1200 = 600.

-3x² + 150x - 1800 = 0.

The coefficients are a = -3, b = 150, c = -1800, hence:

$\Delta = 150^2 - 4(-3)(-1800) = 900$

$x_1 = \frac{-150 + \sqrt{900}}{-6}$

$x_2 = \frac{-150 - \sqrt{900}}{-6} = 30$

He needs to charge $30 for a profit of $600.

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

6 0

2 years ago

CAN ANYONE HELP ME WITH THIS QUESTION!!!!!??? The length of a string in yards is a function f(n) of the length n in inches. Writ

xeze [42]

Your answer would be B f(n)= 1/36 n

5 0

3 years ago

If the 13th and 38th terms of an arithmetic sequence are -53 and -128,

love history [14]

9514 1404 393

Answer:

-2018

Step-by-step explanation:

The n-th term is ...

an = a1 +d(n -1)

So, the given terms are ...

-53 = a1 +12d

-128 = a1 +37d

Subtracting the first from the second gives ...

(a1 +37d) -(a1 +12d) = (-128) -(-53)

25d = -75

d = -3

The 668th term will be ...

a668 = a1 +d(668 -1) = a1 +667d = (a1 +37d) +630d

a668 = -128 +630(-3) = -128 -1890 . . . . substitute for a38

a668 = -2018

7 0

3 years ago