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dalvyx [7]
3 years ago
6

What is the value of k in the function ƒ(x) = 108 – kx if ƒ(–4) = 124?

Mathematics
1 answer:
ruslelena [56]3 years ago
3 0

Answer:

4

Step-by-step explanation:

If f(x)= 108-kx, then all you have to do is plug in the given value of x which is -4, then equal it to the given value of 124.

108 - kx = 124\\108 - k(-4) = 124\\\\108 + 4k = 124\\\\4k = 124 - 108\\\\k = 16/4\\\\k = 4

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By applying the equation of dilation, the coordinates of the vertices of the triangle ABC are A'(x, y) = (-12, 0), B'(x, y) = (0, -9) and C'(x, y) = (-12, -9).

<h3>How to find the image of a triangle</h3>

A dilation is a type of <em>rigid</em> transformation. <em>Rigid</em> transformations are transformations applied to <em>geometric</em> loci such that <em>Euclidean</em> distances are conserved.

There is a triangle and its image must be a triangle, the <em>new</em> triangle is found by transforming the three vertices of the prior one following this formula:

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If we know that P(x, y) = (0, 0), A(x, y) = (-4, 0), B(x, y) = (0, -3) and C(x, y) = (-4, -3), then the new vertices of the triangle are, respectively:

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B'(x, y) = (0, 0) + 3 · [(0, -3) - (0, 0)]

B'(x, y) = (0, -9)

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C'(x, y) = (0, 0) + 3 · [(-4, -3) - (0, 0)]

C'(x, y) = (-12, -9)

Lastly, we draw the two triangles, which are presented in the image attached below.

To learn more on dilations: brainly.com/question/13176891

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