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3 years ago

Tuna simplified the expression 3x^3/12x^-2 to x/4 what was tryna mistake?

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

3 0

Answer:

She added the exponents instead of subtracting them.

Step-by-step explanation:

She was to simplify:

$\frac{3x^3}{12x^-^2}$

Dividing the numerator with 3 and the denominator with three gives:

$\frac{x^3}{4x^-^2}$

Then, x³ ÷ $x^{-2}$ would be $x^{3 - -2}$ = $x^{5}$

(Where there is division; we are supposed to subtract the exponents.)

So the final answer would be: $\frac{x^5}{4}$

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The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –

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The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

$10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2$

The one polynomial addend is,

$-5a^2b^2 +12a^2b - 5$

Let suppose the other polynomial addend is f(a,b). Thus,

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Isolate the second polynomial as,

$f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5$

Arrange the like terms as,

$f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7$

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab is 15a²b²- 20a²b + 6ab² - 4ab + 7.

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Answer:

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For the frequency table showing class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies and histogram

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