Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
Answer:
y = 11/20
Step-by-step explanation:
-4/5 + y = -1/4
Add 4/5 to each side
-4/5 +4/5 + y = -1/4+4/5
y = -1/4 + 4/5
Get a common denominator
y = -1/4 *5/5 + 4/5 *4/4
y = -5/20 + 16/20
y = 11/20
Check
-4/5 +11/20 = -1/4
Get a common denominator
-4/5*4/4 + 11/20 = -1/4*5/5
-16/20 +11/20 = -5/20
-5/20 = - 5/20
Check
I'm just going to give the answers snce so many questions
1. 2
2. 2/(m^2)
3. 1/(16x^8)
4. 3x^4
steps one: the one that starts with squareing both sides (√5x-9)^2=4^2)
23. x=9
24. 0
last graph one: third one (one that starts at 2 up from the origin)
Answer:
2.50$
Step-by-step explanation:
The product (multiplication) of a number w and 737.
737w
