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1 year ago

15

A seal went 15 feet below sea level to catch a fish. A sea lion dove 6 feet less than two times as deep as the seal to catch a l

arger fish. What expression represents the sea lion’s position in relation to sea level?

1 answer:

seropon [69]1 year ago

5 0

Answer:

thx

Step-by-step explanation:

yetehhdydbdihdbdjbduhdhd8hdbidhbfjdhidbbdidhbdhdibdbd

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X = 0<br> Solve.<br> 2.1x - (1 + 2x) = 5.3

HACTEHA [7]

Answer:

<u>-1=5.3</u>

<u />

<em>not sure if this is right; it should be though</em>

<em></em>

Step-by-step explanation:

2.1(0) - (1+2(0))= 5.3

-(1)=5.3

-1=5.3

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2 years ago

(0,1),(1,3),(2,5),(3,7) function rule

DaniilM [7]

$\bf \begin{array}{ccll}x&y\\\cline{1-2}0&1\\[0.8em]1&\stackrel{2(1)+1}{3}\\[0.8em]2&\stackrel{2(2)+1}{5}\\[0.8em]3&\stackrel{2(3)+1}{7}\\[0.8em]x&2x+1\end{array}~\hspace{8em}y=2x+1$

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2 years ago

Find the value of x for brainliest

kvasek [131]

Answer:

Step-by-step explanation:

i believe i and going to get this wrong bc imma idiot, but i would say 49 or 37 ur choice

and its only 5 points so enjoy the memes

can i have brainliest plzz???

7 0

2 years ago

Read 2 more answers

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me

Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

$\mu = \frac{5(0.1) + 2(0.2)}{7} = 0.1286$

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?

This is $P(X = 2)$ . So:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073$

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

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2 years ago

Factor 15x3 – 5x2 + 6x – 2 by grouping

Tanzania [10]

5x2(3x-1)+2(3x-1)factoring furhter gives(5x2+2)(3x-1)

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2 years ago