Evaluate: 3 x 23 x 4² x 3-7x4-2

Use the power-reducing formulas to rewrite the expression as an equivalent expression that does not contain powers of trigonome

Delicious77 [7]

Step-by-step explanation:

Sin^2 (x) * Cos^2 (x) = {[1 - cos (2x)]/2}*{[1 + cos (2x)]/2}

Sin^2 (x) * Cos^2 (x) =[ 1 - cos^2 (2x)]/4

Sin^2 (x) * Cos^2 (x) = (1/4) - (1/4) * cos^2 (2x)

Sin^2 (x) * Cos^2 (x) = (1/4) - (1/4) * {[1 + cos (2*2x)]/2}

Sin^2 (x) * Cos^2 (x) = (1/4) - (1/8) * [1 + cos (4x)]

Sin^2 (x) * Cos^2 (x) = (1/4) - (1/8) - (1/8)* [cos (4x)]

Sin^2 (x) * Cos^2 (x) = (1/8) - (1/8)* [cos (4x)]

6 0

2 years ago

there are two identical fridges for desserts. one of the fridge has 5/8 of its room left and the other fridge is only 1/8 full.

ELEN [110]

Answer:

1.5

Step-by-step explanation:

5/8 + 7/8= 1.5 or 1 1/2

6 0

2 years ago

Read 2 more answers

Sara drives 72 miles on 3.2 gallons of gas. She uses this information to calculate how many miles per gallon she can drive. Usin

nordsb [41]

Answer:

276.75 miles

Step-by-step explanation:

12.3/3.2 × 72 = 276.75 miles

8 0

2 years ago

If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal

lorasvet [3.4K]

Answer:

a

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

b

The probability is $P(Z > 2.5 ) = 0.0062097$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 800$

The variance is $var(x) = 1600 \ kg$

The range consider is $x_1 = 778 \ kg \ x_2 = 834 \ kg$

The value consider in second question is $x = 900 \ kg$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{var (x)}$

substituting value

$\sigma = \sqrt{1600}$

$\sigma = 40$

The percentage of a cucumber give the crop amount between 778 and 834 kg is mathematically represented as

$P(x_1 < X < x_2 ) = P( \frac{x_1 - \mu }{\sigma} < \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma } )$

Generally $\frac{X - \mu }{ \sigma } = Z (standardized \ value \ of \ X)$

So

$P(x_1 < X < x_2 ) = P( \frac{778 - 800 }{40} < Z< \frac{834 - 800 }{40 } )$

$P(x_1 < X < x_2 ) = P(z_2 < 0.85) - P(z_1 < -0.55)$

From the z-table the value for $P(z_1 < 0.85) = 0.80234$

and $P(z_1 < -0.55) = 0.29116$

So

$P(x_1 < X < x_2 ) = 0.80234 - 0.29116$

$P(x_1 < X < x_2 ) = 0.51118$

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

$P(X > x ) = P(\frac{X - \mu }{\sigma } > \frac{x - \mu }{\sigma } )$

substituting values

$P(X > x ) = P( \frac{X - \mu }{\sigma } >\frac{900 - 800 }{40 } )$

$P(X > x ) = P(Z >2.5 )$

From the z-table the value for $P(Z > 2.5 ) = 0.0062097$

7 0

2 years ago

Factorise<br><br> 3-x^2<br><br> Someone answer this question please

densk [106]

Answer:

No factors.

3 - x^2 is prime.

Step-by-step explanation:

4 0

1 year ago

Evaluate: 3 x 23 x 4² x 3-7x4-2​

Evaluate: 3 x 23 x 4² x 3-7x4-2