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Aleks04 [339]
3 years ago
7

6) Find b(10) in the sequence given by b(n) = -5 + 9(n-1). b(10) =?

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

76

Step-by-step explanation:

1. Replace n with 10. The equation will look like:

-5+9(10-1)

2. Remember PEMDAS! The first step in solving the equation is solving whatever is in the parenthesis:

-5+9(9)

3. The next step is exponents, but since there aren't exponents in the equation, we move to multiplication and division. The equation should now look like this:

-5+81

4. Now we move on to addition and subtraction; add the two numbers!

-5+81=76

There's your answer!! Hope this helped :)

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6у – 6 = 4у + 16<br> A.y=2.2<br> B. y= -2.2<br> C. у= 11<br> D. у= 5
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Answer:

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Answer:

1:A(-6,-1) B(-14,0) C(-11,4)

2:D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3:H(-4,1) I(-4, 6) J(0,6) K(0,1)

Step-by-step explanation:

Before we begin, lets define the transformations:

(x, y)

T(a, b) = (x+a, y +b)

Rxaxis = (x, -y)

Ryaxis = (-x, y)

r(180, 0) = (-x, -y)

D.5(1/2x, 1/2y)

R(-90, O) = (-y, x)

1. T. A(6,-1) B(14,0) C(11,4)

   Rx. A(6, 1) B(14,0) C(11,-4)

   r180 A(-6,-1) B(-14,0) C(-11,4)

2. Rx D(-12,-6) E(-4,-6) F(-6, -9) G(-10, -9)

   Ry D(12,-6) E(4,-6) F(6, -9) G(10, -9)

   D.5 D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3. Rx=1 H(-1,2) I(4, 2) J(4,-2) K(-1,-2)

   T H(1,4) I(6, 4) J(6,0) K(1,0)

   r-90 H(-4,1) I(-4, 6) J(0,6) K(0,1)

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