Answer: how do you solve for this
Step-by-step explanation:
Answer:41 − 45; 46 − 50; 51 − 55; 56 − 60
Step-by-step explanation:
Answer and Explanation:
Her alternative hypothesis is that there is some difference between the means of the ages of the audiences of the two television programs. That is, the mean ages of the two audiences are not the same.
If the mean of the ages of the audiences of television programme 1 (COPS) is xbar₁
And the mean of the ages of the audiences of the television programme 2 (60 minutes) is xbar₂
Her alternative hypothesis can be represented mathematically as
xbar₁ - xbar₂ ≠ 0
The answer would be line segment.
If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
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