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Sergeeva-Olga [200]
3 years ago
9

Petra jogs 5 miles in 40 minutes. At this rate, how long would it take her to jog 7 miles?

Mathematics
2 answers:
nlexa [21]3 years ago
8 0
You could write and solve an equation of ratios:

    5 mi          7 mi
------------ = ----------
 40 min           x

Then 5x = 280, and x = 56.  Petra can jog 7 miles in 56 minutes.
Wittaler [7]3 years ago
6 0
(40 min)/(5 mi) = (time)/(7 mi) . . . . . the rates are the same
(7/5)*(40 min) = time = 56 min

At the same rate, it would take Petra 56 minutes to jog 7 miles.
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\mathrm{Multiply\:and\:divide\:by\:10\:for\:every\:number\:after\:the\:decimal\:point.}

\mathrm{There\:are\:}3\mathrm{\:digits\:to\:the\:right\:of\:the\:decimal\:point,\:therefore\:multiply\:and\:divide\:by\:}1000

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216,\:1000

\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

2,\:3\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:3\cdot \:3\cdot \:3

2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5

\mathrm{The\:prime\:factors\:common\:to\:}216,\:1000\mathrm{\:are\:}

=2\cdot \:2\cdot \:2

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:2=8

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=\frac{8\cdot \:27}{8\cdot \:125}

\mathrm{Cancel\:the\:common\:factor:}\:8

=\frac{27}{125}

Hence, the correct answer is =\frac{27}{125}

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