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3 years ago

identify an equation in point slope form for the line parallel to y=-2/8x+8 that passes through (4,-5)

Mathematics

1 answer:

lawyer [7]3 years ago

5 0

Step-by-step explanation:

the point-slope form is

y - y1 = m(x - x1)

where (x1, y1) is a point on the line.

m is the slope of the line, which is always (in any form) the factor of x.

the parallel line has -2/8 as factor of x, which is therefore also the slope of our new line (after all, it has to be parallel, so it must have the same slope).

so, we have

y + 5 = -2/8 × (x - 4)

which can be simplified, of course, to

y + 5 = -1/4 × (x - 4)

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Leokris [45]

Answer:

see explanation

Step-by-step explanation:

(1)

the sine of an angle = $\frac{opposite}{hypotenuse}$

(a)

here the opposite is 12 and the hypotenuse is 13

12 is the side opposite ∠DEF ← required angle

(b)

the tangent of an angle = $\frac{opposite}{adjacent}$

here the opposite is 5 and the adjacent is 12

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(2)

to calculate AB use Pythagoras' identity in the right triangle

AB² = 2² + 3² = 4 + 9 = 13, hence

AB = $\sqrt{13}$ ≈ 3.6 ( to nearest tenth )

tanB = $\frac{2}{3}$ ⇒ B = 33.7°

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3 years ago

The polygons are similar, but not necessarily drawn to scale. Find the value of x.

alexandr402 [8]

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Let's plug the values and solve for x:

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Multiply both sides by x to get

$x^2=4 \iff x=\pm2$

The only feasible solution, though, is $x=2$ , because it wouldn't make sense to have negative lengths.

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Aleksandr [31]

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Step-by-step explanation:

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