All categories

3 years ago

Please answer no links

Mathematics

2 answers:

max2010maxim [7]3 years ago

6 0

Answer:

56.54in^2

Step-by-step explanation:

kow [346]3 years ago

4 0

Answer:

18π in^2 (roughly 56.5 in^2)

Step-by-step explanation:

The area of a semicircle is half the area of a circle. So the area would be 1/2πr² instead of πr².

Since the diameter is 12 inches, the radius would be half of that, making the radius r=12/2=6 inches.

Plugging in r=6 into our formula, we see that the area of the semicircle is 1/2π(6)²=1/2π(36)=18π inches^2

So your final area is 18π in^2 (roughly 56.5 in^2)

You might be interested in

HHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH

Ulleksa [173]

Answer:

what is wrong with you bro

7 0

3 years ago

2) The equation y = 18x represents the relationship between 2, the number of hours biked, and

Inessa05 [86]

Answer:(2,36)and (3,54)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is the solution for the inequality given below? Show work. 3x - 4 < -19

Ludmilka [50]

Answer:

$x$

Step-by-step explanation:

$3x-4$

Add 4 to both sides

$3x$

Divide both sides by 3

$x$

Hope this helps!

(Please mark brainliest)

5 0

3 years ago

Read 2 more answers

Name the property the equation illustrates. 6(-6/2) = (-6/2)6

blondinia [14]

Inverse property of multiplication.

4 0

3 years ago

Read 2 more answers

Please help ASAP If f(x) = x^2-6x+2 and g(x) =sqrt x find a.) (fog) (x) b.) (gof) (-2)

Rudik [331]

$\large\begin{array}{l} \left\{\!\begin{array}{l} \mathsf{f(x)=x^2-6x+2}\\ \mathsf{g(x)=\sqrt{x}}\\ \end{array}\right. \end{array}$

$\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}$

______

$\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}$

______

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2181559

$\large\textsf{I hope this helps. :-)}$

Tags: composite function composition evaluate algebra

7 0

3 years ago