Find, correct to the nearest degree, the three angles of the triangle with the vertices d(0,1,1), e( 2, 4,3) − , and f(1, 2, 1)
Ksju [112]
Well, here's one way to do it at least...
<span>For reference, let 'a' be the side opposite A (segment BC), 'b' be the side opposite B (segment AC) and 'c' be the side opposite C (segment AB). </span>
<span>Let P=(4,0) be the projection of B onto the x-axis. </span>
<span>Let Q=(-3,0) be the projection of C onto the x-axis. </span>
<span>Look at the angle QAC. It has tangent = 5/4 (do you see why?), so angle A is atan(5/4). </span>
<span>Likewise, angle PAB has tangent = 6/3 = 2, so angle PAB is atan(2). </span>
<span>Angle A, then, is 180 - atan(5/4) - atan(2) = 65.225. One down, two to go. </span>
<span>||b|| = sqrt(41) (use Pythagorian Theorum on triangle AQC) </span>
<span>||c|| = sqrt(45) (use Pythagorian Theorum on triangle APB) </span>
<span>Using the Law of Cosines... </span>
<span>||a||^2 = ||b||^2 + ||c||^2 - 2(||b||)(||c||)cos(A) </span>
<span>||a||^2 = 41 + 45 - 2(sqrt(41))(sqrt(45))(.4191) </span>
<span>||a||^2 = 86 - 36 </span>
<span>||a||^2 = 50 </span>
<span>||a|| = sqrt(50) </span>
<span>Now apply the Law of Sines to find the other two angles. </span>
<span>||b|| / sin(B) = ||a|| / sin(A) </span>
<span>sqrt(41) / sin(B) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(41) / sqrt(50) = sin(B) </span>
<span>.8222 = sin(B) </span>
<span>asin(.8222) = B </span>
<span>55.305 = B </span>
<span>Two down, one to go... </span>
<span>||c|| / sin(C) = ||a|| / sin(A) </span>
<span>sqrt(45) / sin(C) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(45) / sqrt(50) = sin(C) </span>
<span>.8614 = sin(C) </span>
<span>asin(.8614) = C </span>
<span>59.470 = C </span>
<span>So your three angles are: </span>
<span>A = 65.225 </span>
<span>B = 55.305 </span>
<span>C = 59.470 </span>
Answer:
4,500 cubic units
Step-by-step explanation:
Answer:
Inequality = $.20t + $10 > $0.25t
Step-by-step explanation:
$.20t + $10 > $0.25t
- $.20t > $.20t
-------------------------------
$10 > .05t
------ > ------
.05 > .05t
$200 > t
T is less than however many texts equals $200 for the other company.
The text messages for the Newsom Wireless is less than 1000 texts because $200 ( the total cost for all text messages sent ) that Gator Cellular has is greater than the total amount of cost per text message that Newsom Wireless has.
I am not sure if this is correct but I gave you the inequality. Not sure how to solve this because we don't know what the variable T stands for.
The area of the portion of the windshield cleaned by the 10-in wiper blade is 106.85in² .
We have been provided that the Length of blade is 15 inches and the Angle of rotation = 98°
We are required to calculate the area of the portion of the windshield cleaned by the 10-in wiper blade.
We have to solve this by using area of a sector.
Area of a sector = ½r²θ
where θ is in radians.
So, angle of rotation (98°) must first be converted to radians
Converting 98º to radians, we get
98×π/180 = 49π/90
The area of the region swept out by the wiper blade
= (area of the sector where r = 15 and θ = 49π/90) - (area of the sector where r = (15-10) and θ = 49π/90).
So, Area = ½×15²×49π/0 - ½×5²×49π/90
= ½×49π/90(15²-10²)
= 49π/180× (225 - 100)
= 49π/180 × 125
= 1225π/36
Area = 106.8472in²
=106.85 in²
Hence, the area of the portion of the windshield cleaned by the 10-in wiper blade is 106.85in²
To know more about area of a sector- brainly.com/question/7512468
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