Answer
The steel ball will be caught up in between the mercury and water medium.
Step-by-step explanation:
- Mercury with a density of 13546 kg/m^3
- water with a density of 1000 kg/m^3
- Steel with a density of 8050 kg/m^3
From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.
The steel ball will be caught in between both mixtures as the density of steel is 8050 kg/m^3.Which is more than Water but less than Mercury.
From fraction to decimal: divide the numerator by the denominator
From decimal to percent: move the decimal two places to the right. For example: 0.062=6.2%
From percent to decimal: move the decimal point two steps to the left. For example: 56%=0.56
From decimal to fraction: Rewrite the decimal number number as a fraction (example: <span>2.625=<span>2.6251</span></span>) an then Multiply by 1 to eliminate 3 decimal places, we multiply numerator and denominator by 10 cubed = 1000<span><span><span>2.625/1</span>×<span>1000/1000</span>=<span>2625/1000 and don forget to reduce if possible;)
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Answer: They show numerical value. You have to make them clear.
Step-by-step explanation:
1/2 is the simpliest form,divide everything by 2
Answer:
One possible equation is 
, which is equivalent to 
.
Step-by-step explanation:
The factor theorem states that if 
(where 
is a constant) is a root of a function, 
would be a factor of that function.
The question states that 
and 
are 
-intercepts of this function. In other words, 
and 
would both set the value of this quadratic function to 
. Thus, 
and 
would be two roots of this function.
By the factor theorem, 
and 
would be two factors of this function.
Because the function in this question is quadratic, and would be the only two factors of this function. In other words, for some constant 
(
):
.
Simplify to obtain:
.
Expand this expression to obtain:
.
(Quadratic functions are polynomials of degree two. If this function has any factor other than and , expanding the expression would give a polynomial of degree at least three- not quadratic.)
Every non-zero value of corresponds to a distinct quadratic function with -intercepts and . For example, with 
:
, or equivalently,
.
