What to do when forget the pasword to the account?

Mathematics

1 answer:

kaheart [24]2 years ago

5 0

Answer:

usually at the login screen it gives you an option to reset your password if you forgot, it will appear in blue as "forgot password?" or "trouble logging in?"

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Solve for k, the constant of variation, in an inverse variation problem where y=17 x=6

torisob [31]

Answer:

k = 102

Step-by-step explanation:

Inverse variation is represented as follows:

y = k/x

Find k by substituting 17 for y and 6 for x:

17 = k/6

Multiplying both sides by 6 results in k = 102

8 0

3 years ago

Juan drove 360 miles in 5 hours.

Brrunno [24]

Answer:

it would take him to 7 hours drive 504 miles.

Step-by-step explanation:

360 miles → 5 hours

1 miles → (5/360) hours

504 miles → [(5/360)*504] hours

504 miles → 7 hours

5 0

3 years ago

Read 2 more answers

Wayne and Winston are scuba diving and are ascending to the surface. The function y = 30x − 105 represents Wayne’s elevation in

arsen [322]

The function that represents Wayne´s elevation:
y = 30 x - 105
The function that represents Winston´s elevation:
- 100 = 0 m + b
b = -100
-16 = 3m - 100
3 m = 84
m = 84 : 3 = 28
y = 28 x - 100
Surface level: y = 0
Wayne:
0 = 30 x - 105
x = 3.5 minutes
Winston:
0 = 28 x - 100
x = 3.57 minutes
If they both ascend at the same rate, Wayne will be first to the surface.

5 0

4 years ago

A research study investigated differences between male and female students. Based on the study results, we can assume the popula

oksian1 [2.3K]

Answer: 0.0548

Step-by-step explanation:

Given, A research study investigated differences between male and female students. Based on the study results, we can assume the population mean and standard deviation for the GPA of male students are µ = 3.5 and σ = 0.05.

Let $\overline{X}$ represents the sample mean GPA for each student.

Then, the probability that the random sample of 100 male students has a mean GPA greater than 3.42:

$P(\overline{X}>3.42)=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{3.42-3.5}{\dfrac{0.5}{\sqrt{100}}})\\\\=P(Z>\dfrac{-0.08}{\dfrac{0.5}{10}})\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=P(Z>1.6)\\\\=1-P(Z$