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earnstyle [38]
3 years ago
5

Suppose y varies directly with x. Write a direct variation equation that relates x and y.

Mathematics
1 answer:
timama [110]3 years ago
8 0

\huge\mathfrak\purple{Answer:-}

★ <u>Option (A) y = -5x</u> is the right answer.

<h2><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u></h2>

<h3>I hope this helps! :)</h3>
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Between which two integers does -13/3 lie?
Tcecarenko [31]

Answer:

-4 and -5

Step-by-step explanation:

- 13/3 is equal to -4.3 so this is why i think this but it maybe wrong.

5 0
4 years ago
Consider the following sequence of numbers
Tcecarenko [31]

Answer:

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3 0
3 years ago
Giving brainliest! 5 (4m +2)
mart [117]

5(4m+2)\\\\=20m+10

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3 years ago
Plz help ill give u brainlist
g100num [7]
Step One
Find the base area  of the large hexagon as though the smaller one was not removed.

Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.

Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)

Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.

Area of the remaining piece = area of large hexagon - area of the small hexagon

Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)

Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18

I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3

3 0
3 years ago
29 = v+17 what the answer cs ion get it
Alexus [3.1K]

Answer:

12

Step-by-step explanation:

29 = v + 17

29 - 17 = v

12 = v

6 0
2 years ago
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