PLS HELP ME ASAP WITH NUMBER 9 THANK YOUU

Mathematics

1 answer:

s2008m [1.1K]2 years ago

4 0

9a)
4x - 2 + 30 = 68
4x + 28 = 68
4x = 40
x = 10

9b)
y = 180 -68
y= 112

You might be interested in

There are 8 pencils in package.how many packages will be needed for 28 children if each child get 4 pencils

sashaice [31]

8 pencils = 1 package
28 children need pencils
Each child gets 4 pencils

28x4 = 112 (pencils needed)

112/8 = 14 packages needed.

7 0

2 years ago

What is the prime factorization of 60

jeka57 [31]

Answer:

2*2*3*5

Step-by-step explanation:

We need to factor 60 until it is prime numbers

60 = 12*5 5 is prime 12 is not

=3*4 *5 3,5 prime 4 is not

= 3 *2*2 *5 2,3,5 are prime

Rearranging the order

=2*2*3*5

5 0

3 years ago

Xander needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items.

Aleksandr [31]

Answer:

c ≥ 56 is the REQUIRED INEQUALITY.

Step-by-step explanation:

Here, the given question is INCOMPLETE.

Xander needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items. Choose the inequality and solution to represent the number of cans, c, that Xander must still collect.

Now, here:

The number of cans Xander needed to collect = At least 120

The number of items already collected = 64

c: the number of cans, c, that Xander must still collect.

Now, the number of cans to be collected - Cans already collected

= 120 - 64 = 56

So, the number of can he must collect to make a TOTAL OF AT LEAST 120 cans = 56 cans

⇒ The number of cans to be collected ≥ 56 cans

⇒c ≥ 56 cans

or, c ≥ 56 is the REQUIRED INEQUALITY.

3 0

2 years ago

Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4

djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

$\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty$