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2 years ago

PLEASE HELP I NEED QUALITY ANSWERS AS WELL WILL MARK BRAINLIEST!!!

Mathematics

1 answer:

hammer [34]2 years ago

4 0

Answer:

True

Step-by-step explanation:

So the radius would be 5 (as you times it by 2 to get 10)

Therefore

2a=10 is the same as what the circle with diameter d=2r=10

You might be interested in

If there are 120 calories in 4 ounces of hot fudge, how many calories are in 8

miss Akunina [59]

Answer:

240 calories

Step-by-step explanation

You're doubling the amount of fudge, so double the amount of calories. You could also think of it as 2 4-oz portions of fudge, then just add the calories (120+120) together.

3 0

2 years ago

Twice the difference between a number

Alecsey [184]

Answer:

Let x = the number

2(x-5) = 9

2x - 10 = 9

2x = 19

x = 9.5

Step-by-step explanation:

7 0

2 years ago

weqwewe [10]

Answer:

y = 4x -19

Step-by-step explanation:

y = 4x + b

first we add the point to the equation and then we solve for b

-3 = 4 ( 4 ) + b

-3 = 16 + b

-16

-19 = b

7 0

2 years ago

Find the distance and the midpoint of the line segment with endpoints (-1,4) and (-5,3)

Marina CMI [18]

Answer:

see explanation

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 1,4) and (x₂, y₂ ) = (- 5, 3)

d = $\sqrt{(-5+1)^2+(3-4)^2}$

= $\sqrt{(-4)^2+(-1)^2}$

= $\sqrt{16+1}$ = $\sqrt{17}$ ≈4.12 ( to 2 dec. places )

To find the midpoint use the midpoint formula

[0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

Using the same points as above then

midpoint = [0.5(- 1- 5), 0.5(4 + 3 ) ] = [0.5(- 6), 0.5(7) ] = (- 3, 3.5 )

4 0

3 years ago

Can you solve 27,28,39,30,31,32,33,34?

kozerog [31]

Answer:

27. x^7

28. 4x^13

29. 1/f^4

30. x^5

31. 2x^14

32. (4y^3 x^2)^2

33. (2y/x)^6

Step-by-step explanation:

$27. \: \: \frac{ {x}^{ - 1} }{ {x}^{ - 8} } \\ \frac{ {x}^{8} }{ {x}^{1} } \\ {x}^{8 - 1} = {x}^{7} \\$

$28. \: \: \: \frac{ {52x}^{6} }{ {13x}^{ - 7} } \\ \frac{ {52x}^{6} {x}^{7} }{13} \\ {4x}^{6 + 7} = {4x}^{13}$

$29. \: \: {f}^{ - 3} ( {f}^{2} )( {f}^{ - 3} ) \\ {f}^{( - 3) +2 + ( - 3) } \\ {f}^{ - 4} \\ \frac{1}{ {f}^{4} } \\$

$30. \: \: \frac{ {x}^{ - 4} }{ {x}^{ - 9} } \\ \frac{ {x}^{9} }{ {x}^{4} } \\ {x}^{9 - 4} = {x}^{5}$

$31. \: \: \frac{ {24x}^{6} }{ {12x}^{ - 8} } \\ \frac{ {24x}^{6} {x}^{8} }{12} \\ {2x}^{6 + 8} = {2x}^{14} \\$

$32. \: \: \frac{ {3x}^{2} {y}^{ - 3} }{ {12x}^{6} {y}^{3} } \\ \frac{ {3x}^{2} }{ {12x}^{6} {y}^{3} {y}^{3} } \\ \frac{ {x}^{2 - 6} }{ {4y}^{3 + 3} } \\ \frac{ {x}^{ - 4} }{ {4y}^{6} } \\ \frac{1}{ {4y}^{6} {x}^{4} } = \frac{1}{({ {4y}^{3} {x}^{2} ) }^{2} }$

$33. \: \: {( {2x}^{3} {y}^{ - 3}) }^{ - 2} \\ {2x}^{3 \times - 2} {y}^{ - 3 \times - 2} \\ {2x}^{ - 6} {y}^{6} \\ \frac{ {2y}^{6} }{ {x}^{6} } \\ {( \frac{2y}{x} )}^{6} \\$

4 0

1 year ago