CS902 Module3 Homework1

What is the effect of this program?

Mrac [35]

Answer:

The answer is (C)

Let’s run the algorithm on a small input to see the working process.

Let say we have an array {3, 4, 1, 5, 2, 7, 6}. MAX = 7

Now for i=0, i < 7/2, here we exchange the value at ith index with value at (MAX-i-1)th index.

So the array becomes {6, 4, 1, 5, 2, 7, 3}. //value at 0th index =3 and value at (7-0-1)th index is 6.

Then for i=1, i < 7/2, the value at index 1 and (7-1-1)=5 are swapped.

So the array becomes {6, 7, 1, 5, 2, 4, 3}.

Then for i=2, i < 7/2, the value at index 2 and (7-2-1)=4 are swapped.

So the array becomes {6, 7, 2, 5, 1, 4, 3}.

Then for i=3, i not < 7/2, so stop here.

Now the current array is {6, 7, 2, 5, 1, 4, 3} and the previous array was{3, 4, 1, 5, 2, 7, 6}.

Explanation:

So from the above execution, we got that the program reverses the numbers stored in the array.

8 0

3 years ago

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

A research team is studying parallel computing. They want to run parallel process without having to use multiple processors. How

aleksandr82 [10.1K]

I wanna say threads bc cores r processors. And one can run multiple threads. Double check tht :)

5 0

3 years ago

I need to create a method named "root positive". which will either print the square root of the number passed to it or if the nu

rjkz [21]

Answer:

Explanation:

The following code is written in Java. It is a method that calculates the square root of a number as requested. The method first checks with an IF statement if the parameter value is a positive number and then calculates the square root and prints it to the screen. Otherwise, it prints Number must not be negative. A test case has been provided in the main method and the output can be seen in the attached image below.

import java.util.Scanner;

class Brainly {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.print("Enter a number of type double to calculate square root:");

double num = in.nextDouble();

rootPositive(num);

}

public static void rootPositive(double num) {

if (num > 0) {

System.out.println(Math.sqrt(num));

} else {

System.out.println("Number must not be negative.");

}

5 0

3 years ago

The option to add the date and time to a document is located in the

Tomtit [17]

Answer:

The option to add the date and time to a document is located in the

text grouping on the Insert tab.

Explanation:

8 0

3 years ago

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