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2 years ago

8, 12, 16, ... Find the 49th term

Mathematics

1 answer:

Ivanshal [37]2 years ago

5 0

Answer:

200

Step-by-step explanation:

the above is an arithmetic progressions

number of terms of an AP = a+( n -1 )d

a= first term= 8

d= common difference= 12-8= 4

49th term:

= 8+(49-1)4

= 8+(48)4

= 8+192= 200

therefore, the 49th term is 200

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Point B has coordinates (1,2). The x-coordinate of point A is negative 8. The distance between point A and point B is 15 uni

olchik [2.2K]

Answer:

The point A will be (-8,14) or (-8,-10).

Step-by-step explanation:

Point B has coordinates (1,2) and the x-coordinate of point A is - 8.

Let us assume that the coordinates of point A are (-8,k).

Now, given that the point A is 15 units apart from point B.

Therefore, from the distance formula, we can write that

$\sqrt{(1 - ( -8))^{2} + (2 - k)^{2}} = 15$

Now,squaring both sides, we get

$(1 - ( -8))^{2} + (2 - k)^{2} = 225$

⇒ $(2 - k)^{2} = 225 - 9^{2} = 144$

⇒ 2 - k = ± 12

⇒ k = 14 or -10.

Therefore, the point A will be (-8,14) or (-8,-10). (Answer)

We know that the distance between two points on the coordinate plane ( $x_{1}, y_{1}$ ) and ( $x_{2}, y_{2}$ ) is given by

$\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}$ .

7 0

3 years ago

Which of the following expressions are equivalent

Ber [7]

It’s 2 and 3 bc 6a+12 and then 3(2a+4) and you need to distribute for that so 3 times 2a equals 6a and 3 times 4 equals 12 so you get 6a+12

5 0

2 years ago

Read 2 more answers

Middle School Math Medium Level

Nata [24]

Answer:

Its 0, 1.

Step-by-step explanation:

ItsQuipo on yt

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2 years ago

SOMEONE HELP WITH THIS PLZZ!!

Natali5045456 [20]

Answer:

x=90 y=45

Step-by-step explanation:

Answer is C

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3 0

2 years ago

Solve.

Nikitich [7]

The answer is C: $10\text{ }^1/_2$ . Here are the details:

$\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6$

$\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3$

$\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6$

$26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6$

5 0

3 years ago