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1 year ago

8, 12, 16, ... Find the 49th term

Mathematics

1 answer:

Ivanshal [37]1 year ago

5 0

Answer:

200

Step-by-step explanation:

the above is an arithmetic progressions

number of terms of an AP = a+( n -1 )d

a= first term= 8

d= common difference= 12-8= 4

49th term:

= 8+(49-1)4

= 8+(48)4

= 8+192= 200

therefore, the 49th term is 200

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Can anyone help me set up a system of equations for these problems??

statuscvo [17]

Answer:

L = the length of the field

W = the width of the field

The First Question:

The system is: L - 12 = w

2L + 2W = 76

Plug in L - 12 for W and you will get

2L + 2L - 24 = 76

4L -24 = 76

4L = 100

L = 25

To find W do L - 12 = w

25 - 12 = w

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2 years ago

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2 years ago

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Answer:

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2 years ago

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Step-by-step explanation:

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2 years ago

Read 2 more answers

the verticales of triangle XYZ are X(-3,-6),Y(21,-6),and Z(21,4). What is the perimeter of the triangle

andrezito [222]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

X(-3, -6), Y(21, -6). Substitute:

$XY=\sqrt{21-(-3))^2+(-6-(-6))^2}=\sqrt{24^2+0^2}=\sqrt{24^2}=24$

X(-3, -6), Z(21, 4). Substitute:

$XZ=\sqrt{(21-(-3))^2+(4-(-6))^2}=\sqrt{24^2+10^2}=\sqrt{576+100}=\sqrt{676}=26$

Y(21, -6), Z(21, 4). Substitute:

$YZ=\sqrt{(21-21)^2+(4-(-6))^2}=\sqrt{0^2+10^2}=\sqrt{10^2}=10$

The perimeter of the triangle XYZ:

$P_{\triangle XYZ}=XY+XZ+YZ$

Substitute:

$P_{\triangle XYZ}=24+26+10=60$

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2 years ago