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matrenka [14]
3 years ago
15

Your goal in training for the race is to run more than 50 miles per week. So far this week you have run 32 miles. Which inequali

ty represents the situation?
A. d - 32 > 50
B. d + 32 ≥ 50
C. d ≥ 18
D. d + 32 > 50
Mathematics
1 answer:
timama [110]3 years ago
8 0

Answer:

the answer is D

Step-by-step explanation:

You have to run MORE than and not just 50 miles, because of this it wont be B, it wont be A because you have run it already.

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Evaluate h -2 g for h = 3 and g = 27.
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Evaluate h -2 g for h = 3 and g = 27.plug in both values...
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51

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Help me please i dont understand
kipiarov [429]

Answer:

C=75.36

A=452.16

Step-by-step explanation:

C=2x3.14xr

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A=3.14×r^{2}

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5 0
3 years ago
Find the distance between the points (<br> -<br> 10,12) and (15,12).
Nitella [24]
The distance formula is:

d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

We are given two points in the form (x,y), so plug in the values to the distance formula:

d= \sqrt{(-10-15)^2-(12-12)^2}

Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:

d= \sqrt{(-25)^2}

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5 0
3 years ago
An English professor assigns letter grades on a test according to the following scheme. A: Top 15% of scores B: Scores below the
lisabon 2012 [21]

Answer:

59 to 66

Step-by-step explanation:

Mean test scores = u = 74.2

Standard Deviation = \sigma = 9.6

According to the given data, following is the range of grades:

Grade A: 85% to 100%

Grade B: 55% to 85%

Grade C: 19% to 55%

Grade D: 6% to 19%

Grade F: 0% to 6%

So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.

6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for  0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)

The formula for z score is:

z=\frac{x-u}{\sigma}

For z = -1.56, we get:

-1.56=\frac{x-74.2}{9.6}\\\\ x = 59

For z = -0.88, we get:

-0.88=\frac{x-74.2}{9.6}\\\\ x = 66

Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)

7 0
4 years ago
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