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Alla [95]
2 years ago
12

Findthe domain of the function f(x) = √19-x​

Mathematics
2 answers:
Jet001 [13]2 years ago
7 0

Answer:

(-∞,19)

Definition: The domain of a function is the set of input or argument values for which the function is real and defined

antoniya [11.8K]2 years ago
4 0

Answer:

<u>(-∞, 19]</u>

Step-by-step explanation:

The domain of this function is only true for all real values of f(x).

That means the lower limit of the function is -∞ as the values are positive, and the upper limit is 19, because that is the greatest value it can become before becoming negative.

The domain is : <u>(-∞, 19]</u>

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12. (2v^3 - v + 8) + (-v^3 + v - 3)<br><br> 14. (4h^3 + 3h + 1) - (-5h^3 + 6h - 2)
Lana71 [14]
12. On addition, you can just combine like terms.
2v^3+(-v^3)=v^3
-v+v cancels each other out
8+(-3)=5
So you have v^3+5

14 On subtraction, you have to remember to distribute the negative sign so after you do that you have:
4h^3+3h+1+5h^3-6h+2
Then you can combine like terms
4h^3+5h^3=9h^3
3h-6h=-3h
1+2=3
So you end up with:
9h^3-3h+3

Hope that helps and feel free to ask any questions.
7 0
3 years ago
Classify the following triangle. Check all that apply.
diamong [38]
There’s nothing to answer or any work for people to respond
6 0
3 years ago
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A line with a slope of 2 passes through the point (6,4). What is its equation in
m_a_m_a [10]

Answer:

y=2x-8

Step-by-step explanation:

y-y1=m(x-x1)

y-4=2(x-6)

y=2x-12+4

y=2x-8

7 0
2 years ago
According to the bar graph, which teacher gave 16 minutes of homework on Wednesday?
Natasha_Volkova [10]
Ms.Jones gave sixteen minutes of homework
4 0
3 years ago
If the sine of an angle equals to {2}/{5}, then the tangent of the angle could be:
Leona [35]

Answer:

If the sine of an angle equals to {2}/{5}, then the tangent of the angle could be:

<em>5. \frac{2}{\sqrt{21} }</em>

Step-by-step explanation:

  • Imagine a triangle
  • The sine of an angle is equal to the length of the opposite leg over the hypotenuse.
  • <em>HINT: SOHCAHTOA</em>

<u>To find the adjacent leg (a): </u>

Using the pythagorean theorem: a^{2} + b^{2} =c^{2}

- <em>a </em>and <em>b</em> are the lenght of the sides and <em>c </em>is the hypotenuse

we know one side and the hypotenuse. Therefore plugging into the formula we get:

a^{2} + 2^{2} =5^{2}

where <em>a</em> is the adjacent leg of the triangle, solving for a we get:

a^{2} =5^{2}- 2^{2}

a^{2} = 21

a = \sqrt{21}

<u>To find the tangent of the angle: </u>

Since tangent is opposite leg over the adjacent leg:

tan θ = \frac{2}{\sqrt{21} }

4 0
3 years ago
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