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san4es73 [151]
4 years ago
13

What is the value of "c" in the quadratic equation 3x 2 + 5x + 7 = 0? 3 5 7

Mathematics
2 answers:
stich3 [128]4 years ago
8 0
C= 7

3x^2+5x+7
ax^2+bx+C
dmitriy555 [2]4 years ago
7 0

Answer:

c=7

Step-by-step explanation:

They are just asking you to compare

ax^2+bx+c=0 to

3x^2+5x+7=0.

What constant values are in the place of a,b, \text{ and } c.

a=3

b=5

c=7

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Mama L [17]
525 is what i got as my answer good luck





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4 years ago
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How would I solve n^2=2n
lidiya [134]

Answer: n=0 or n=2

Step-by-step explanation: Step 1: Subtract 2n from both sides.

n²−2n=2n−2n

n²−2n=0

Step 2: Factor left side of equation.

n(n−2)=0

Step 3: Set factors equal to 0.

n=0 or n−2=0

n=0 or n=2

5 0
3 years ago
What is the fraction that is equal to 0.534
Mandarinka [93]

Answer:

267/500

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0.534 = 534 / 1000

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3 0
3 years ago
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Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 60 minutes earlier than Car 2 and averages 40 mp
prohojiy [21]

Answer:

The two cars will be almost 188 miles far from each other.

Step-by-step explanation:

Travel Time for Car 1 = t = 3.5 hours

Travel time for Car 2 = t-1 = 3.5 - 1 = 2.5 hours

Average speed of car 1 = 40 mph

Average speed of car 2 = 50 mph

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Distance Traveled by Car 2 = 50*2.5 = 125 miles

As both the roads are at a 90 degree angle. The path of the two cars and the joining line of their final position forms a right angle triangle where:

altitude = a = 140

base = b = 125

Distance of cars after 3.5 hours = c = ?

According to Pythagoras theorem:

c^2 = a^2 + b^2

c^2 = 140² + 125²

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Almost 188 miles.

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3 years ago
Find all the critical points of the function <img src="https://tex.z-dn.net/?f=%20f%28x%29%3D%20%28x%2B1%29%2F%28x-3%29%20" id="
yulyashka [42]

The function

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has derivative

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which has no zeros. It is undefined at x=0, the only critical point. The derivative is negative for all values of x, so the function is decreasing everywhere in its domain.

Your function

... y = (x+1)/(x-3)

can be written as

... y = 1 +4/(x-3)

which is a version of y = 1/x that has been vertically scaled by a factor of 4, then shifted 1 unit up and 3 units to the right. Shifting the function to the right means x=3 is excluded from the domain (and the interval on which the function is decreasing).

The critical point is x=3.

The function is decreasing on (-∞, 3) ∪ (3, ∞), increasing nowhere.

5 0
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