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Olenka [21]
2 years ago
9

Please help! [4 x 3⁵ - 9 x (-7)] + 3³ (-4² +2²) - 11 Give your answer in simplest form.

Mathematics
1 answer:
Pani-rosa [81]2 years ago
4 0

Answer:

Please see the question below.

Step-by-step explanation:

In the expression "[4 x 3⁵ - 9 x (-7)]" I'm unclear if the "x" is a multiplication sign, or the variable x.  I'll assume it is the variable x in my answer.

4 x 3⁵ = 972x

- 9 x (-7) = 63x

3³ (-4² +2²)  = 27 (20) = 540

-11 = -11

========

Putting it all together:

972x + 63x + 540 -11

1035x + 529

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Answer:

answer: 189

Step-by-step explanation:

Formula to find triangles area is base x height ÷ 2 So... 7 x 10 = 70 70 ÷ 2 = 35 Now sense we have 4 identicle triangles we will just do 35 × 4 amd 35 × 4 = 140 now for the square its simply just base x height so 7 × 7 = 49 now we will add these up...140 + 49 = 189 so 189 is the area. Hope this helps!

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3 years ago
What is the value of -32+(-4+7)(2)?<br> -28<br> -3<br> 3<br> 15
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Answer:

-26

Step-by-step explanation:

  1. -32+3×2
  2. -32+6
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By using BODMAS, any of the answers given is correct!

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The pie store is having a 10% off sale on all of its pies. If the pie you want regularly costs $18, how much would you save with
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Select from the drop-down menus to correctly complete each statement
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Y axis for the first and what are the options for the second anwser
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Hey Bestie! 50 pts Pls help! Real answers only pls &lt;3
frosja888 [35]

Answer:

1. \: 3i

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2>1. \:  \sqrt{ - 9}</h2>

\sqrt{ - 1(9)}

\sqrt{ - 1}  \times  \sqrt{  9}

i \times  \sqrt{9}

i \times  \sqrt{ {3}^{2} }

i \times 3

3i

<h2>2. \:  \sqrt{ - 8}</h2>

\sqrt{ - 1(8)}

\sqrt{ - 1}  \times  \sqrt{8}

i \times  \sqrt{8}

i \times  \sqrt{ {2}^{2} \times 2 }

2i \sqrt{2}

<h2>3. \:  \sqrt{ - 80}</h2>

\sqrt{ - 1}  \times  \sqrt{80}

i \times  \sqrt{80}

4i \:  \sqrt{5}

<h2>4. \:  \sqrt{ - 75}</h2>

\sqrt{ - 1}  \times   \sqrt{75}

i \times  \sqrt{75}

i \times  \sqrt{ {5}^{2} \times 3 }

5i \sqrt{3}

<h2>5. \:  \sqrt{ - 72}</h2>

\sqrt{ - 1}  \times  \sqrt{72}

i \times  \sqrt{72}

i \times ( {6}^{2}  \times 2)

6i \sqrt{2}

<h2>6.  \sqrt{ - 20}</h2>

\sqrt{ - 1}  \times  \sqrt{20}

i \times  \sqrt{20}

i \times  \sqrt{ {2}^{2}  \times 5}

2i \sqrt{5}

<h2>7. \:  \sqrt{ - 27}</h2>

\sqrt{ - 1}  \times  \sqrt{27}

i \times  \sqrt{27}

i \times  \sqrt{ {3}^{2}  \times 3}

3i \sqrt{3}

<h2>8. \:  \sqrt{ - 12}</h2>

\sqrt{ - 1 \times 12}

i \times  \sqrt{12}

i \times  \sqrt{4(3)}

2i \sqrt{3}

<h2>9. \:  \sqrt{ - 125}</h2>

\sqrt{ - 1}  \times  \sqrt{125}

i \times  \sqrt{ {5}^{2} \times 5 }

5i \sqrt{5}

<h2>10. \:  \sqrt{ - 180}</h2>

\sqrt{ - 1}  \times  \sqrt{180}

i \times  \sqrt{ {6}^{2} \times 5 }

6i \sqrt{5}

<h3>Hope it is helpful...</h3>
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