Question

Find the solution to the system of equations: x 3y = 7 and 2x 4y = 8 1. isolate x in the first equation: 2. substitute the value for x into the second equation: 3. solve for y: 4. substitute y into either original equation: 5. write the solution as an ordered pair: x = 7 – 3y 2(7 – 3y) 4y = 8 14 – 6y 4y = 8 14 – 2y = 8 –2y = –6 y = 3 x 3(3) = 7 ( , )

Answer 1

The solution to the system of equation are x = -2 and y = 3

How to find the solution of a system of equation?

x + 3y = 7

2x + 4y = 8

Let's isolate x in the first equation

x = 7 - 3y

substitute the value of x in the second equation.

Therefore,

2(7 - 3y) + 4y = 8

14 - 6y + 4y = 8

-2y = 8 - 14

-2y = -6

y = -6 / -2

y = 3

Hence,

x + 3(3) = 7

x = 7 - 9

x = -2

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