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photoshop1234 [79]
4 years ago
11

A cereal manufacturer has a tolerance of .75

Mathematics
1 answer:
miv72 [106K]4 years ago
5 0

let the absolute weight of the box of cereal be X

20-0.75 ≤ x ≤ 20+0.75

19.25 ≤ x ≤ 20.75

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Connor jogs at a constant rate of 3.5 miles per hour. The table shows the distance traveled for different numbers of hours. Drag
allsm [11]

Answer:

1st and 3rd go in the 1st box

2nd and 4th go in the 2nd box

last one goes in the last box

Step-by-step explanation:

1,2,3,4,5 and time spent jogging go in independent quantity

3.5, 7, 10.5, 14, 17.5 and distance traveled go in dependent quantity

m=3.5h goes in neither

3 0
3 years ago
Fifteen and one third multiply by twelve equals what
Diano4ka-milaya [45]

15 \frac{1}{3}  \times 12
1st, change 15 & one third into improper fraction

\frac{46}{3}
Then Multiply them

\frac{46}{3}  \times  \frac{12}{1}
= 184
6 0
3 years ago
How is (or how can you make) y/(1-x) equal to (1+x)/y
Musya8 [376]
I hope this helps you

4 0
3 years ago
For this problem, assume that three students are chosen from 5 freshmen, 4 sophomores, and 4 juniors.
Sati [7]

The formula C(n, r)= \frac{n!}{r!(n-r)!}, where r! is 1*2*3*...r

is the formula which gives us the total number of ways of forming groups of r objects, out of n objects.

for example, given 10 objects, there are C(10,6) ways of forming groups of 6, out of the 10 objects.


<span>The sample space S in our problem is as follows: </span>

triples selected from 5 freshmen, 4 sophomores, and 4 juniors, so that at least 1 freshman is selected.

The selection of 1 freshman can be done in 5 ways. The selection of the remaining 2 out of 4 freshmen (one is already chosen), 4 sophomores, and 4 juniors can be done in C(12, 2) many ways.

C(12, 2)=\displaystyle{  \frac{12!}{2!10!}= \frac{12\cdot11\cdot10!}{2!10!}=66

So there are in total, 5*66= 330 possible triples.

n(S)=330


The event E "selecting 2 freshmen and 1 junior" can occur in :

C(5, 2)\cdot 4=\displaystyle{ \frac{5!}{2!3!}\cdot4=40 many ways.


so n(E)=40


P(E)=n(E)/n(S)=40/330=0.12



Answer: 0.12


 

4 0
3 years ago
which has a greater effect on the volume - changing the radius by a given amount or changing the height by the same amount/ why?
AURORKA [14]
Assuming we’re talking about a cylinder, whose volume formula is V = pi r^2 h…

It will have a greater effect to change a variable’s value that has a greater power on it.

Changing h from 1 to 2 doubles the volume.
Changing r from 1 to 4 quadruples the volume, because 1^2 = 1 and 2^2 = 4. The effect of the change on r is amplified by the power.
3 0
3 years ago
Read 2 more answers
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