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N76 [4]
2 years ago
12

14.Evaluate the expression 4x2+3y for x = 5 and y =6.answer?

Mathematics
2 answers:
Marat540 [252]2 years ago
6 0

Step-by-step explanation:

Given: x=5 and y=6

=>4x2+3y

=> 8+3(6)

=> 8+18

=> 26

<em><u>Hope </u></em><em><u>it </u></em><em><u>helps </u></em>

AnnyKZ [126]2 years ago
3 0

The value of this expression is 58

<h3>             </h3>

Algebraic expression is a mathematical sentence that involves all mathematical operations.

In an algebra - a real number is always accompanied by some letter, which can represent a variable or unknown.

   

— To solve this expression, just: change the letters for the numbers and multiply/add.

<h3>               </h3>

⚘ Resolution

\large \sf 4x2+3y

\large \sf 4 \cdot 5 \cdot 2 +3 \cdot 6

\large \sf 40 +18

\red{\boxed{\boxed{\green{\large \sf \  58 \  }}}}\\

Therefore, the value of this expression will be 58

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Evaluate x/y + 3z^2 for x= 2/3, y= 6/7, and z=3
prohojiy [21]

x/y + 3z^2 for x= 2/3, y= 6/7, and z=3

=2/3  /  6/7  + 3(3^2)

=2/3 * 7/6 + 3(9)

= 7/9 + 27

= 7/9 + 243/9

= 250/9

answer is a. 250/9

6 0
3 years ago
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Question: Researchers in Pakistan wanted to better understand the effects of anthracycline (a chemotherapeutic drug) on the hear
Sedbober [7]

Using the normal distribution, it is found that:

1. His z-score was of Z = -1.88.

2. There is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

3. Z-score of z = 1.85, there is a 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

4. Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 1.35.
  • The standard deviation is of \sigma = 0.33.

Item 1:

Considering his ratio, we have that X = 0.73, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.73 - 1.35}{0.33}

Z = -1.88

His z-score was of Z = -1.88.

Item 2:

The probability is the <u>p-value of Z = -1.88</u>, hence, there is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

Item 3:

Score of X = 1.96, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.96 - 1.35}{0.33}

Z = 1.85

The probability is 1 subtracted by the p-value of Z = 1.85, hence, 1 - 0.9678 = 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

Item 4:

Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

More can be learned about the normal distribution at brainly.com/question/24663213

7 0
2 years ago
If 2 dozens of eggs cost #300. How much will 5 eggs cost?
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answer:62.5

a dozen=12 eggs

12× 2 eggs=300

5 eggs=x

cross multiply

24x=1500

thus x=62.5

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Travels by 2 so therefore the answer is B
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I think the answer is c

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