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romanna [79]
2 years ago
14

Compare the two integers: -10 and -3

Mathematics
2 answers:
Sunny_sXe [5.5K]2 years ago
5 0

Answer:

−10<−3

Step-by-step explanation:

Natali [406]2 years ago
5 0

Answer:

-10 is more and -3 is less

Step-by step explanation:

cause it is just by looking

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Find the area of the circle. Leave your answer in terms of π. radius is 14 in.
Ray Of Light [21]

The formula of the area of the circle:

π × radius^2

In this case, given that the radius is 14 inches:

π × 14^2

=196π square inches

Therefore the answer is 196π square inches.

Hope it helps!

5 0
3 years ago
Angle 1 is 50 degrees. Which angle is also 50 degrees?
solong [7]

Answer:

Step-by-step explanation:

angle 1= 50 degrees

x angle=50 degrees

cross multiply and you get and you get <u><em>1</em></u> as your answer

4 0
3 years ago
Which ordered pair is a solution of the equation?<br> y=7x-2y=7x−2
astra-53 [7]

Answer:

3

Step-by-step explanation:

7x-2y=3

7(1)-2(2)=3

7-4=3

3=3

5 0
3 years ago
The number of children at the liberty was 3 times the number of adults. The total number of people at the liberty was 48. How ma
Black_prince [1.1K]

Answer:  32

Step-by-step explanation:

48 people at the liberty and there are 3 times the number of adults 48 divided by 3 would be 16 kids and 48 - 16 would be 32

5 0
3 years ago
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
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