Question

When Charles randomly chooses a fruit from a basket of apples and oranges, the odds are 5 to 3 that he will select an orange. What is the probability that he chooses 2 oranges, if fruits are not replaced?

Answer 1

It is approximately a 7:20 chance he would draw 2 oranges from the basket.

Answer 2

Answer:

The probability that he chooses 2 oranges is:

                $\dfrac{5}{14}$

Step-by-step explanation:

The odds of choosing a orange from a basket is:

                           $\dfrac{5}{3}$

If  O denote orange

and T denote the total number of fruits

Then the odds of selecting an orange is given by:

 $\dfrac{O}{T-0}=\dfrac{5}{3}$

This means that:

The total number of fruits in basket i.e. T=8

so that the ratio matches.

Hence, the probability of getting orange in first draw= 5/8

Now , the second draw is independent of first and the fruits are not replaced.

This means now we have to choose fruits from remaining 7 fruits in the basket .

Probability of getting orange in second draw is: 4/7

Hence, the probability of choosing 2 oranges if the fruits are not replaced is:

  $=\dfrac{5}{8}\times \dfrac{4}{7}\\\\\\=\dfrac{5}{14}$