You launch a ball at an angle of 35 degrees above the horizontal with an initial velocity of 38 m/s. What is the time the ball w

Question

4 years ago

14

ill stay in the air? [Must show work]

1 answer:

Julli [10] · Answer 1 · 2021-11-15T09:02:17+03:00

Julli [10]4 years ago

7 0

Answer:

t= 2.22 seconds.

Step-by-step explanation:

1) You need to find the vertical velocity.

38*sin(35) = 21.7959

2) You need to use the t=v1y/a formula to find the time to get to the top.

v1y= the vertical velocity, 21.7959

a= Acceleration, 9.8

t=21.7959/9.8

t=2.22