You launch a ball at an angle of 35 degrees above the horizontal with an initial velocity of 38 m/s. What is the time the ball w
ill stay in the air? [Must show work]
1 answer:
Answer:
t= 2.22 seconds.
Step-by-step explanation:
1) You need to find the vertical velocity.
38*sin(35) = 21.7959
2) You need to use the t=v1y/a formula to find the time to get to the top.
v1y= the vertical velocity, 21.7959
a= Acceleration, 9.8
t=21.7959/9.8
t=2.22
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