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ladessa [460]
2 years ago
13

You toss a coin and roll a number cube. Find P(heads and an even number.)

Mathematics
1 answer:
skelet666 [1.2K]2 years ago
4 0

Answer:

<em>The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).</em>

<em>The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).⇒</em>

<em>The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).⇒ P(head and an even number) </em>

<em>The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).⇒ P(head and an even number) = P(head) ×</em><em> P(even number)</em>

<em> P(even number)Assuming a fair coin and a fair die:</em>

<em> P(even number)Assuming a fair coin and a fair die:P(head) </em>

<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%</em>

<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) </em>

<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50%</em>

<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50% (since half the numbers on a die are even).</em>

<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50% (since half the numbers on a die are even).P(head and even number) </em>

<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50% (since half the numbers on a die are even).P(head and even number) =50%×50%</em><em>=25%</em>

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