X+10=110-4x
-x from both sides
10=110-5x
subtract 110 from both sides
-100=-5x
divide both sides by -5
x= 20
D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
i dont know sorry
Step-by-step explanation:
D. 70% because 45/75=0.6 or 60% and 60% doesn't equal to 70%
Hope this helps!!
Answer:
2,7
Step-by-step explanation:
