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Dmitry_Shevchenko [17]
3 years ago
5

How do I find the measure of problem #13

Mathematics
2 answers:
lidiya [134]3 years ago
5 0

Answer:

Set the two equations equal to each other if you want me to solve tell me.

So.... 15x+10=16x+3

-15                  -15

10=1x+3

-3

7=x

madam [21]3 years ago
4 0

Answer:


Step-by-step explanation:

Set them equal bc they are vertical angles

15x+10=6x+3

-6x. -6x

9x=

I don't know the rest

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4 0
3 years ago
(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

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6 0
3 years ago
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Simplified answer would be 60k^2+k

and you get that answer by combining like terms, Good Luck! 

8 0
3 years ago
Read 2 more answers
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Answer:

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7 0
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