A motorcycle rides from point P to Q to R to S and finally to P in a circular path as shown in the below figure. Find a) the dis
1 answer:
The distance covered by the motorcycle is 31.4 km and displacement will be equal to 0.
<h3>What is Distance and Displacement ?</h3>Distance and Displacement both are the measure of the movement of an Object from one point to another.
Distance is a scalar quantity while Displacement is a vector quantity , and so it depends upon direction.
Distance travelled will always be positive but Displacement can be positive , negative and zero.
A motorcycle rides from point P to Q to R to S and finally to P in a circular path as shown in the below figure
The missing figure is attached with the answer.
(a) The distance covered by the motorcycle is
2πr = 2 * 3.14 * 5 = 31.4 km
(b) The displacement will be equal to 0 as the starting and the ending point is same.
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Make an x and y table, and pick any values to plug in for x in the equation.
I will use the numbers from -2 to 2
Now plug in the values you picked for x into the equation to find its y-value
x = -2
y = 3x - 1 Plug in -2 for x
y = 3(-2) - 1
y = -6 - 1
y = -7
x = -1
y = 3x - 1
y = 3(-1) - 1
y = -3 - 1
y = -4
Do the same for the rest of the numbers, and graph each point and draw a line connecting them.
Answer:
Measure of exterior angle ABD = 136°
Step-by-step explanation:
Given:
measure of ∠A = (2x + 2)°
measure of ∠C = (x + 4)°
measure of ∠B = x°
Find:
Measure of exterior angle ABD
Computation:
Using angles sum property
∠A + ∠B + ∠C = 180°
So,
(2x + 2) + (x + 4) + x = 180
4x + 6 = 180
4x = 176
x = 44
So,
measure of ∠B = x°
measure of ∠B = 44°
Measure of exterior angle ABD = 180 - measure of ∠B
Measure of exterior angle ABD = 180 - 44
Measure of exterior angle ABD = 136°
