How do you rewrite 3x-9y=18 as a slop-intercept form?

Mathematics

1 answer:

Norma-Jean [14]3 years ago

5 0

I believe it would be y=-1/3x-2

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Scorpion4ik [409]

Sinθ = (2/3) tanθ < 0 Implies tanθ = Negative.

For sin positive and tan negative, implies θ is in the second quadrant.

Sinθ = (2/3) = opposite / Hypotenuse.

Adjacent side:

x² + 2² = 3²

x² + 4 = 9

x² = 9 - 4

x² = 5

x = √5 = Adjacent.

cosθ = Adjacent / Hypotenuse = √5 / 3

Since θ is in the second quadrant, cosine is also negative in the second quadrant.


Therefore:

cosθ = - (√5/3)

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