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ki77a [65]
2 years ago
11

What is the explicit fomula for this sequence

Mathematics
1 answer:
tigry1 [53]2 years ago
7 0

Answer:

C

Step-by-step explanation:

2(5)^4-1 = 2(5)^3

2*125 = 250 and 250 is the 4th term

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An african elephant weighs 6 tons. what is the weight of the elephant in pounds?
sesenic [268]
6 tons to pounds is 12,000 pounds. So the elephant weighs 12,000 lbs.
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3 years ago
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The approximate land areas of the seven continents are listed in the table below.
Varvara68 [4.7K]

Answer:

6.9 million

Step-by-step explanation:

the median is the number that is in the middle or centre of a set of observations that is arranged either in an ascending or descending order.

Arrange the land areas in ascending order :

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the number in the middle is the 4th number which is 6.9

5 0
3 years ago
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If a gambler places a bet on the number 7 in​ roulette, he or she has a​ 1/38 probability of winning.
SCORPION-xisa [38]
A) The mean would be 1.842 and the standard deviation would be 1.339.
b) It would not be unusually low.

Explanation
a) This can be modeled as a binomial distribution, since there are two outcomes (7 or not 7), the events are independent (getting a 7 on one spin does not influence the chance of a 7 on the next spin) and there are a fixed number of trials (70).  In a binomial distribution, the mean is given by n*p, where n is the number of trials and p is the probability.

μ=n*p=70*(1/38) = 1.842.

The standard deviation of a binomial distribution is given by
σ=√(n*p*(1-p))=√(70(1/38)(37/38)=1.339.

b) To determine if this is unusually low, we find the probability:
_nC_k\times p^n\times (1-p)^{k-n}
\\
\\=_{70}C_0\times (\frac{1}{38})^0\times \frac{37}{38}^{70}
\\
\\=0.15

Since this is not below 0.05, we do not consider this unusual.
3 0
4 years ago
What is 9.63 as a fraction in simplest form?
Allushta [10]
9.63 as a fraction is 9 63/100
3 0
3 years ago
Can you guys please help me in question 12 A B C
MaRussiya [10]
12a
math: 68/85 * 100 = 80%
science: 70*0.9 = 63 number correct
b. Science
c.48

8 0
3 years ago
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