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Maksim231197 [3]
2 years ago
13

You just hung a picture twelve inches above the wall trim.

Mathematics
1 answer:
GenaCL600 [577]2 years ago
4 0
Yes I sure did hang the picture what about it
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One of the legs of a right triangle measures 8 cm and its hypotenuse measures 14 cm.
Ugo [173]

Answer:

about 11.5 cm.

Step-by-step explanation:

I know the measurement of the other leg is about 11.5 cm. I know because I used the Pythagorean theorem.

a^2+b^2=c^2.

"a" and "b" are the values of the legs of the triangle, while "c" is the measure of the hypotenuse. We know that 8cm is the measure of one of the legs, and 14 cm is a measure of the hypotenuse.

8^2+b^2=14^2 simplified: 64+b^2=196

Then, I subtracted 64 on both sides, so I would have "b" by itself.

b^2=132

Next, I found the square root of both b^2 and 132, so I would find the true value of "b."

b=11.4891252931

So, the measure of the other leg rounded to the nearest tenth is about 11.5.

3 0
2 years ago
100 POINT QUESTION!!!!!!!!!!!!!!!!!!!!!!!!!!!!
babunello [35]

Answer:

Ok I don't know waht you mean but the answer is

Step-by-step explanation:

Answer:

x=3/2±(√11)2

x=1.5+1.65831i

x=1.5−1.65831i

Find the Solution for

2x^22−6x+10=0

using the Quadratic Formula where

a = 2, b = -6, and c = 10

x=(−b±√(b^2−4ac))/2a

x=(−(−6)±√((−6)2−4(2)(10)))2(2)

x=(6±√(36−80))/4

x=(6±√−44)/4

The discriminant b^2−4ac<0

so, there are two complex roots.

Simplify the Radical:

x=(6±2√11 i)/4

x=6/4±(2√11 i)4

Simplify fractions and/or signs:

x=3/2±(√11)2

which becomes

x=1.5+1.65831i

x=1.5−1.65831i

4 0
2 years ago
Help me please !!!!!!
PilotLPTM [1.2K]
The correct answer is B. x is greater than -2.

7 0
3 years ago
Rewrite in simplest terms: 4(3d + 7f) – 5f – 3(9f + 3d)
Elena L [17]

Answer:

3d - 4f

Step-by-step explanation:

(12d + 28f) - 5f - (27f + 9d)

12d + 28f - 5f - 27f - 9d

(12-9)d + (28-5-27)f

3d - 4f

don't forget to put bracket, it is fundamental

4 0
2 years ago
Read 2 more answers
Determine the domain of the following graph:
Pani-rosa [81]

Answer:

- 11 \leqslant x \leqslant  + 12

note that -11 itself is not included. the circle is empty, not filled

7 0
2 years ago
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