The answer is 40 your welcome
For this one you can use 3/8 + 3/8 since 3+3 is equals to 6 and the 8 stays as it is.
I hope this helps.
YOU'RE WELCOME :D
0.706 is the answer to your problem
You can obtain the a number for which they all divisors by calculating the least common multiple.
This way:
85 = 5*17*1
17=17*1
19=19*1
4=2^2 *1
2=2*1
The least common multiple is: 5*17*19*2^2 = 6,460.
Then 84, 17, 19, 4 and 2 are all divisors of 6,460.
Answer:
- P(t) = 100·2.3^t
- 529 after 2 hours
- 441 per hour, rate of growth at 2 hours
- 5.5 hours to reach 10,000
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
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(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
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(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
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(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000