Question

Need help checking my work for Trigonometry. Will mark brainist!

Answer 1

Answer:

1.  0.9925  (4 d.p.)

2.  17°

3.  67°

Step-by-step explanation:

Question 2

⇒ sin 83° = 0.9925461516...

⇒ sin 83° = 0.9925 (4 d.p.)

Question 3

$\sf \implies \sin X=0.2923$

$\sf \implies X=\sin^{-1}(0.2923)$

$\implies \sf X=16.99570395...^{\circ}$

$\implies \sf X=17^{\circ}\:\:(nearest\:degree)$

Question 4

Sine Ratio

$\sf \sin(\theta)=\dfrac{O}{H}$

where:

• $\theta$ is the angle
• O is the side opposite the angle
• H is the hypotenuse (the side opposite the right angle)

From inspection of the triangle:

• $\theta$ = W
• O = OS = 24
• H = OW = 26

Substitute the values into the formula and solve for W:

$\implies \sf \sin(W)=\dfrac{24}{26}$

$\implies \sf W= \sin^{-1}\left(\dfrac{24}{26}\right)$

$\implies \sf W=67.38013505...^{\circ}$

$\implies \sf W=67^{\circ}\:\:(nearest\:degree)$