First, tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>), so if cos(<em>θ</em>) = 3/5 > 0 and tan(<em>θ</em>) < 0, then it follows that sin(<em>θ</em>) < 0.
Recall the Pythagorean identity:
sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1
Then
sin(<em>θ</em>) = -√(1 - cos²(<em>θ</em>)) = -4/5
and so
tan(<em>θ</em>) = (-4/5) / (3/5) = -4/3
The remaining trig ratios are just reciprocals of the ones found already:
sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/3
csc(<em>θ</em>) = 1/sin(<em>θ</em>) = -5/4
cot(<em>θ</em>) = 1/tan(<em>θ</em>) = -3/4
Answer:
A rhombus
A rhombus is a flat-shaped quadrilateral-
A ≈ 78.46 ft
To find the answer just look up the formula for finding area with circumference and plug in the circumference
In exponents it could be 3130.51114^2, 213.998224 and 55.95097086
Happy to Help!
Answer:
True
Step-by-step explanation:
angle 3 and 6 are alternate angles.
alternate angles have the following characteristics:
1. they are inside the parallel lines
2. they are on opposite sides of the transversal
3. they are EQUAL
another example of alternate angles is angle 4 and angle 5
