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Nuetrik [128]
2 years ago
15

The product (

Mathematics
1 answer:
Volgvan2 years ago
8 0

(a+b)(a-b) = a^2 - ab + ba - b^2 = a^2 - b^2

Since the middle terms cancel each other out, what is left is the difference of two squares.

In your example (x+6)(x-6) = x² -36

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Will Mark Brainlest helpppp​
Anvisha [2.4K]

Answer:

R = \left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]

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P - Q + R = I ( I is the identity matrix )

\left[\begin{array}{ccc}2&4\\3&5\\\end{array}\right] - \left[\begin{array}{ccc}-2&2\\4&1\\\end{array}\right] + R = \left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right] ( subtract corresponding elements )

\left[\begin{array}{ccc}2-(-2)&4-2\\3-4&5-1\\\end{array}\right] + R = \left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]

\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right] + R = \left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]

R = \left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right] - \left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right] = \left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]

6 0
3 years ago
What is the solution to the system of equations below?
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