A - False
B - True
C - True
D - False
E - True
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7.84 / 2 = 3.92
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
Step-by-step explanation:
We want to write an exponential function that goes through the points (0, 20) and (6, 1280).
The standard exponential function is given by:
The point (0, 20) tells us that <em>y</em> = 20 when <em>x</em> = 0. Hence:
Simplify:
So, our exponential function is now:
Next, the point (6, 1280) tells us that <em>y</em> = 1280 when <em>x</em> = 6. Thus:
Solve for <em>b</em>. Divide both sides by 20:
Therefore:
![b=\sqrt[6]{64}=2](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B6%5D%7B64%7D%3D2)
Hence, our function is:
The park formed like a rectangle so :
Area = length × width
Area = ( 9/10 ) × ( 4/5 )
Area = 9 × 4 / 10 × 5
Area = 9 × 2 × 2 / 5 × 5 × 2
Area = 18 / 25
Answer:
Step-by-step explanation:
2/3 30/60 30
