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Butoxors [25]
4 years ago
8

find four consecutive even integers such that 2 times the sum of the first and second is 14 more than 3 times the fourth.

Mathematics
1 answer:
motikmotik4 years ago
8 0
Let the first integer  be x, then:-

2 (x + x+ 2) = 3(x + 6) + 14

4x + 4 = 3x + 18 + 14
x = 18 + 14 - 4 = 28 

the four  integers are 28,30,32 and 34.

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Which pair of functions represents a decomposition of f(g(x)) = | 2(x + 1)^2 + (x + 1) | ?
Ann [662]

Answer:

\Large \boxed{\mathrm{\bold{D.}} \ f(x) = | 2x^2 + x | \ \mathrm{and} \ g(x) = (x + 1)}

Step-by-step explanation:

f(g(x)) = | 2(x + 1)^2 + (x + 1) |

The first option :

f(x) = (x + 1)^2 \ \mathrm{and} \ g(x) = | 2x + 1 |

f(g(x))=(|2x+1|+1)^2

The second option :

f(x) = (x + 1) \ \mathrm{and} \ g(x) = | 2x^2 + x |

f(g(x))=(|2x^2 +x|+1)

The third option :

f(x) = | 2x + 1 | \ \mathrm{and} \ g(x) = (x + 1)^2

f(g(x))=|2(x+1)^2 +1 |

The fourth option :

f(x) = | 2x^2 + x | \ \mathrm{and} \ g(x) = (x + 1)

f(g(x))= | 2(x + 1)^2 + (x + 1) |

3 0
3 years ago
Read 2 more answers
What is the inter-quartile range of the given data set? 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25
Anastasy [175]

Hello!

First of all, we will want to find the median first. We have 11 values here, so we will want to find the 6th number in our data set to find the median. This median will cut our data in half.

15,16,17,18,19,20,21,22,23,24,25

To find the IQR, we need to find the median of each side of our data set now. We exclude the 20, and look for the median on each side. This would be the third number. This gives us our 1st and 3rd quartiles.

15,16,17,18,19,20,21,22,23,24,25

Now, to find the IQR, we subtract the first and third quartiles.

23-17=6

Therefore, our IQR is \boxed {6}.

I hope this helps!

3 0
3 years ago
Read 2 more answers
(x÷5) + (x÷3) = 8/15<br><br><br> Help please!
Tamiku [17]

x\div5=\dfrac{x}{5},\ x\div3=\dfrac{x}{3}\\\\(x\div5)+(x\div3)=\dfrac{8}{15}\\\\\dfrac{x}{5}+\dfrac{x}{3}=\dfrac{8}{15}\ \ \ \ \ |\cdot15\\\\15\cdot\dfrac{x}{5}+15\cdot\dfrac{x}{3}=15\cdot\dfrac{8}{15}\\\\3\cdot\dfrac{x}{1}+5\cdot\dfrac{x}{1}=1\cdot\dfrac{8}{1}\\\\3x+5x=8\\\\8x=8\ \ \ \ |:8\\\\\boxed{x=1}

6 0
4 years ago
The function f is defined by f(x)=3x^2-6. Find f(4z)
nlexa [21]
F(4z) = 3 * (4z)^2 - 6
       =  48z^2 - 6
6 0
4 years ago
Make the appropriate conclusion. Choose the correct answer below. A. RejectReject H0. There is insufficientinsufficient evidence
timama [110]

Answer:

a) Option D is correct.

H0​: μ = 71

Ha​: μ > 71

b) Option F is correct

z > 1.28

c) z = 2.85

d) Option C is correct.

Reject H0.There is sufficient evidence at the α = 0.10 level of significance to conclude that the true mean heart rate during laughter exceeds 71 beats per minute.

Step-by-step explanation:

a) For hypothesis testing, the first thing to define is the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.

This question aims to test the the true mean heart rate during laughter exceeds 71 beats per minute.

Hence, the null hypothesis is that there isn't sufficient evidence to say that the true mean heart rate during laughter exceeds 71 beats per minute. That is, the true mean doesn't exceed 71 beats per minute.

And the alternative hypothesis is that there is sufficient evidence to say that the true mean heart rate during laughter exceeds 71 beats per minute.

Mathematically,

The null hypothesis is represented as

H₀: μ = 71

The alternative hypothesis is represented as

Hₐ: μ > 71

b) Using z-distribution, the rejection area is obtained from the confidence level at which the test is going to be performed. Since the hypothesis test tests only in one direction,

Significance level = (100% - confidence level)/2

0.10 = 10% = (100% - confidence level)/2

20% = 100% - (confidence level)

Confidence level = 100% - 20% = 80%

Critical value for 80% confidence level = 1.28

And since we are testing if the true mean heart rate during laughter exceeds 71 beats per minute, the rejection area would be

z > 1.28

c) The test statistic is given as

z = (x - μ)/σₓ

x = sample mean = 73.4

μ = 71

σₓ = standard error = (σ/√n)

σ = 8

n = Sample size = 90

σₓ = (8/√90) = 0.8433

z = (73.4 - 71) ÷ 0.8433

z = 2.846 = 2.85

d) Since the z-test statistic obtained, 2.85, is firmly in the rejection area, z > 1.28, we reject the null hypothesis, accept the alternative hypothesis and say that there is sufficient evidence at the α = 0.10 level of significance to conclude that the true mean heart rate during laughter exceeds 71 beats per minute.

Hope this Helps!!!

4 0
3 years ago
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