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Umnica [9.8K]
1 year ago
9

Please help i dont get this at all so please i will highly appreciate it .Thank youuu!!!

Mathematics
1 answer:
svlad2 [7]1 year ago
6 0

Answer:

D

Step-by-step explanation:

definitely

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HELP PLEASE!!!!!!!!!!!
emmainna [20.7K]

Answer:

Part 1) y=-x^{2}  ---> Translated up by 1 units

Part 2) y=x^{2}+1  ---> Reflected across the x-axis

Part 3) y=-(x+1)^{2}-1  ---> Translated left by 1 unit

Part 4) y=-(x-1)^{2}-1 ----> Translated right by 1 unit

Part 5) y=-x^{2}-1  ----> Reflected across the y-axis

Part 6) y=-x^{2}-2  ----> Translated down by 1 unit

Step-by-step explanation:

we know that

The parent function is

y=-x^{2}-1 ----> this is a vertical parabola open downward with vertex at (0,-1)

<em>Calculate each case</em>

Part 1) Translated up by 1 unit

The rule of the translation is

(x,y) -----> (x,y+1)

so

(0,-1) ----> (0,-1+1)

(0,1) ----> (0,0) ----> the new vertex

The new function is equal to

y=-x^{2}

Part 2) Reflected across the x-axis

The rule of the reflection is

(x,y) -----> (x,-y)

so

(0,-1) ----> (0,1) ----> the new vertex

The new function is equal to

y=x^{2}+1

Part 3) Translated left by 1 unit

The rule of the translation is

(x,y) -----> (x-1,y)

so

(0,-1) ----> (0-1,-1)

(0,1) ----> (-1,-1) ----> the new vertex

The new function is equal to

y=-(x+1)^{2}-1

Part 4) Translated right by 1 unit

The rule of the translation is

(x,y) -----> (x+1,y)

so

(0,-1) ----> (0+1,-1)

(0,1) ----> (1,-1) ----> the new vertex

The new function is equal to

y=-(x-1)^{2}-1

Part 5) Reflected across the y-axis

The rule of the reflection is

(x,y) -----> (-x,y)

so

(0,-1) ----> (0,-1) ----> the new vertex

The new function is equal to

y=-x^{2}-1

Part 6) Translated down by 1 unit

The rule of the translation is

(x,y) -----> (x,y-1)

so

(0,-1) ----> (0,-1-1)

(0,1) ----> (0,-2) ----> the new vertex

The new function is equal to

y=-x^{2}-2

3 0
3 years ago
The perimeter of a rectangle is 12 meters. If the length of the rectangle is 5 meters, what is the width (in meters)?
kicyunya [14]

Answer:

Step-by-step explanation:

the answer is explained in the picture

7 0
2 years ago
Read 2 more answers
Tiffany earns an annual income of $55,000. After she pays taxes, her take home pay is $41,800. What
SVETLANKA909090 [29]

Answer:

24%

Step-by-step explanation:

Taxes

t = 55000 - 41800

t = 13200

% tax

p = 13200/55000 * 100

p = 24%

5 0
2 years ago
Please dont ignore, Need help!!! Use the law of sines/cosines to find..
Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

<h3>16</h3>

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

  • \sin{A} = \sin{103\textdegree{}},
  • The opposite side of angle A a = BC = 26,
  • The angle C is to be found, and
  • The length of the side opposite to angle C c = AB = 6.

\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}.

\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}.

\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}.

Note that the inverse sine function here \sin^{-1}() is also known as arcsin.

<h3>17</h3>

By the law of cosine,

c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C},

where

  • a, b, and c are the lengths of sides of triangle ABC, and
  • \cos{C} is the cosine of angle C.

For triangle ABC:

  • b = 21,
  • c = 30,
  • The length of a (segment BC) is to be found, and
  • The cosine of angle A is \cos{123\textdegree}.

Therefore, replace C in the equation with A, and the law of cosine will become:

a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}.

\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}.

<h3>18</h3>

For triangle ABC:

  • a = 14,
  • b = 9,
  • c = 6, and
  • Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}.

\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}.

\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree.

<h3>15</h3>

For triangle DEF:

  • The length of segment DF is to be found,
  • The length of segment EF is 9,
  • The sine of angle E is \sin{64\textdegree}}, and
  • The sine of angle D is \sin{39\textdegree}.

Apply the law of sine:

\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}

\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9.

7 0
3 years ago
How can you use a point on the graph of f –1(x) = 9x to determine a point on the graph of f(x) = log9x?
Anastasy [175]

Whenever you can invert a function, you have that the graphs of f(x) and its inverse f^{-1}(x) are reflected with respect to the line y=x

So, given any point on the graph of f^{-1}(x), you can simply swap its coordinates to get the correspondent point on the original function f(x)

As an example, all exponential functions pass through the point (0,1), while all the logarithmic functions pass through the point (1,0)

6 0
3 years ago
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