<span>12a^3b + 8a^2b^2 − 20ab^3
</span>12a^3b = 4ab(3a^2)
8a^2b^2 = 4ab(2ab)
20ab^3 = 4ab(5b^2)
GCF = 4ab
12a3b + 8a2b2 − 20ab3 = 4ab(3a^2 + 2ab - 5b^2)
Add, -11.5x and move it over to 8.5x
Then, subtract them together and you get 20x + 51.86 = 51.76
And you move (subtract) 51. 86 over to 51.76, subtract that and you get 20x = -0.1
Divide, and your answer is -200
Answer:
x = 28 (So it takes 28 hours for the temperature to reach 0°C.)
y = -70 (So the temperature when the experiment begins is −70°C.)
Step-by-step explanation:
To find the the x value, you remove the y value or replace it with 0.
0 = 5/2x - 70
Next you move the variable.
70 (2/5) = x (multiply 70 by 2 to get 140 and divide that by 5)
And now you simplify to get:
28
To find the y value, you remove the x value or replace it with 0.
y = 0 - 70
And now you simplify to get:
-70
x = 28
y = -70
It is already simplified, three goes into three once but three cant go into 32 without there being a remainder.
