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hram777 [196]
1 year ago
9

I need hard and easy math questions with the answer, i need 10 questionsthnx

Mathematics
1 answer:
nydimaria [60]1 year ago
8 0

Answer:

https://www.khanacademy.org/

Step-by-step explanation:

I am not entirely sure what you mean however if you sign up for this website and go to whichever grade level you need you can practice all you want

You might be interested in
1. Pedro is a good student.<br> a.<br> b.
ICE Princess25 [194]

Answer:

your answer is (A)

Step-by-step explanation:

in the affirmative

plz mark me as brainlist

5 0
3 years ago
Which expression is equivalent to3 (1 + x)+7
ivann1987 [24]

Expressions equivalent to 3(1+x)+7 is x+10

6 0
3 years ago
Find the equation of the tangent line and normal line to the curve y=(6+4x)2 at the point (6,900). Write the equations of the li
Ksenya-84 [330]

Answer:

Equation of the tangent to the curve

y = 240x - 215994

Equation of the normal

y = (-1/240)x + 9.75 = - 0.00417x + 9.75

Step-by-step explanation:

y = (6 + 4x)² = 36 + 48x + 16x² = 16x² + 48x + 36

dy/dx = 32x + 48

At the point (6,900),

dy/dx = 32(6) + 48 = 240

Equation of the tangent at point (a,b) is

(y - b) = m(x - a)

a = 6, b = 900, m = 240

y - 6 = 240(x - 900)

In the y = mx + b form,

y - 6 = 240x - 216000

y = 240x - 215994

The slope of the normal line = -(1/slope of the tangent line) (since they're both perpenducular to each other)

Slope of the normal line = -1/240

Equation of normal

y - 6 = (-1/240)(x - 900)

y - 6 = (-x/240) + 3.75

y = (-1/240)x + 9.75

y = - 0.00417x + 9.75

8 0
3 years ago
Petra jogs 2 miles in 24 minutes. At this rate, how long would it take her to jog 10 miles?
mestny [16]

Answer:

120 Minutes

Step-by-step explanation:

24 minutes / 2 miles = 12 minutes / 1 mile

12 minutes / 1 miles = x minutes / 10 miles

Cross multiply

12*10/1 = x

120 / 1 = x

x = 120

Hope that helps!

6 0
3 years ago
Find the coordinates of the point (x,y,z) on the planez=4x+3y+1 which is closest to the origin.
Nataliya [291]
Given plane &Pi; : f(x,y,z) = 4x+3y-z = -1
Need to find point P on &Pi;  that is closest to the origin O=(0,0,0).

Solution:
First step: check if O is on the plane &Pi; : f(0,0,0)=0 &ne; -1 => O is not on &Pi;
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e. 
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane &Pi; , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane &Pi;
Answer: P(-2/13, -3/26, 1/26) is the point on &Pi; closest to the origin.

8 0
3 years ago
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