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Mazyrski [523]
3 years ago
8

To maintain her income, Susan must work 50 hours each week. Susan works 7 hours on Monday, Tuesday, and Wednesday, and 8 hours o

n Thursday. If the variable t stands for the amount of time over the rest of the week Susan will have to work to meet her goal, which of the following units could apply to that variable? A. hours B. jobs C. dollars D. weeks
Mathematics
1 answer:
Damm [24]3 years ago
8 0
A. hours, since the variable is referring to the time
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B 1/2

Step-by-step explanation:

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3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

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Consider a population of Pacific tree frogs (Pseudacris regilla). In this population of frogs, a single locus controls the produ
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Answer: The answer is 62.32

Step-by-step explanation:

See attachment

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3 years ago
What is the relationship between 0.04 and 0.004
podryga [215]
0.004 is one tenth of 0.04 or 0.04 is ten times 0.004
3 0
3 years ago
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Arte-miy333 [17]
A^2 - 6a/a-6 • a+3/a
a(a - 6)/(a - 6) • a+3/a
a • (a + 3)/a
a(a+3)/a
a+3.

The correct solution to this question would be B. a+3.
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3 years ago
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