Find, to the nearest degree, the minimum angle between u(x) andv(x) mathmatica

Valerie is saving money for a new backpack. The one she wants costs $57.65. If she saves 7.25 a week, about how many weeks will

AVprozaik [17]

Answer:

8 weeks

Step-by-step explanation:

Given Valerie want's to buy a backpack which costs $57.65

Also given that she saves $7.25 a week

Let the number of weeks she saves the money be x

For her to buy the backpack the following inequality should be satisfied

amount saved > cost of the item

The amount saved = $Saving per week \times number of weeks$

7.25x > 57.65

x > 7.95

Since x is an integer we have x = 8

Therefore she has to save 8 weeks to buy the item

3 0

3 years ago

How do you turn 3/4 into a decimal?

Dahasolnce [82]

Answer: 0.75

Step-by-step explanation:

100/4=25

25*3 = 75

0.75

4 0

3 years ago

Read 2 more answers

Two cylindrical containers, C and D, with different capacities are shown below. What is the total volume of liquid held in these

Zielflug [23.3K]

Answer:

Option D. (x + 4)(x + 1)

Step-by-step explanation:

From the question given above, the following data were obtained:

C = (6x + 2) L

D = (3x² + 6x + 9) L

Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:

Volume in C = ½C

Volume in C = ½(6x + 2)

Volume in C = (3x + 1) L

Volume in D = ⅓D

Volume in D = ⅓(3x² + 6x + 9)

Volume in D = (x² + 2x + 3) L

Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:

Volume in C = (3x + 1) L

Volume in D = (x² + 2x + 3) L

Total volume =?

Total volume = Volume in C + Volume in D

Total volume = (3x + 1) + (x² + 2x + 3)

= 3x + 1 + x² + 2x + 3

= x² + 5x + 4

Factorise

x² + 5x + 4

x² + x + 4x + 4

x(x + 1) + 4(x + 1)

(x + 4)(x + 1)

Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.

6 0

3 years ago

Solve the differential equation.<br><br> dp/dt = t^2p - p + t^2 - 1

Alborosie

$\frac{dp}{dt} = t^2 p - p + t^2 - 1 \Rightarrow \frac{dp}{dt} = p(t^2 - 1)+ 1(t^2 - 1 ) \Rightarrow \\
\\
\frac{dp}{dt} = (p+1)(t^2 - 1)\ \Rightarrow\ \frac{dp}{p+1} = \left(t^2 - 1\right)dt\ \Rightarrow \\ \\
\int \frac{dp}{p+1} =\int \left(t^2 - 1\right)dt\ \Rightarrow \ \ln|p+1| = \frac{1}{3}t^2 - t + C \ \Rightarrow \\ \\
|p+1| = e^{t^3/3 - t + C}\ \Rightarrow\ p+1 = \pm e^Ce^{t^3/3 - t} \Rightarrow \\ \\
p = Ke^{t^3/3 -t} - 1,\ \text{where $K = \pm e^C$}
$

Since $p = -1$ is also a solution, $K$ can equal 0, and hence, $K$ can be any real number.

7 0

3 years ago

Tell me everything I need to know and please work out the problems

dem82 [27]

Answer:

You basically need to solve for m

I can try to solve it for you:

if you Multiply both sides by 3/2.

you will get 3/8 as your answer

sooooo your answer is m=3/8

6 0

3 years ago